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3 years ago

Evaluate 3 - (-1) + (-1) - 3.

Mathematics

2 answers:

lara [203]3 years ago

8 0

Answer:

Step-by-step explanation:

3 - (-1) + (-1) -3 =

Minus and a negative makes it positive. In other words it would be written like this: 3 + 1 + (-1) - 3 =

Next step would be making it minus 1, because plus sign and negative makes the number to be subtracted. It would be rewritten like this: 3 + 1 - 1 - 3 =

Then you will simply add 3 and 1, which makes it 4. So it would be rewritten likes this: 4 - 1 - 3 =

Then you will simply subtract 1 from 4, which would equal to 3. So it would be rewritten like this: 3 - 3 =

Last step, would be subtracting 3 from 3. Whatever is subtracted from itself would always be 0.

So the answer would be 0!

Vedmedyk [2.9K]3 years ago

7 0

The answer is 0 because a negative times a negative is a positive, and a positive times a negative is negative, then it would be 3+1-3 and it’s 0.

Answer: 0

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John is 3 years older than Jim. Jim is 4 years less than twice David’s age. How old are the three boys if their ages add up to 3

gulaghasi [49]

Answer:

15 years , 12 years , 8 years.

Step-by-step explanation:

Given:

John is 3 years older than Jim.

Jim is 4 years less than twice David’s age.

Ages of three boys add up to 35.

Question asked:

How old are the three boys?

Solution:

Let age of David = $y$

Let age of Jim = $x$

Then age of John will be = $x + 3$

As Jim is 4 years less than twice David’s age

Equation will be , $x = 2y - 4$

Multiplying both side by 2

= $2x = 4y - 8$ (let equation 1 )

As ages of three boys add up to 35.

Equation will be, $x + (x + 3) + y = 35$

= $2x + 3 + y = 35$

Subtracting both side by 3

= $2x + y = 32$

= $2x = - y + 32$ (let equation 2 )

subtracting equation 1 and 2,we get

= $2x = - y + 32$

= $2x = 4y - 8$

= $0 = - 5y + 40$

= $5y = 40$

dividing both side by 5

$= y = 8$ (David ages)

Then ( age of Jim) $x = 2y - 4$

$x = 2 \times8 - 4$

= $16 - 4$

= $12 years$

Then age of John will be, $x + 3$

$= 12 + 3$

= $15 years$

Thus, age of John = 15 years

Age of Jim = 12 years

Age of David = 8 years

7 0

3 years ago

Dr. Burger rides his bike to work in the mornings. Usually, he leaves his house at 8:20 and gets to the office at 9:00 riding at

Vika [28.1K]

Answer:

40 mph

Step-by-step explanation:

40 mins to bike usually, which means he bikes 10 miles. He needs to bike at a minimum of 10 miles in 15 mins, which translates to 40 miles in an hour.

P.S. He is going to surely be late.

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2 years ago

How far above ground is the top of the pole?

Arisa [49]

Answer:

I would say about 7 feet and 1 inch

Step-by-step explanation:

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3 years ago

Applying Inverse Properties In Exercise,apply the inverse properties of logarithmic and exponential functions to simplify the ex

Kryger [21]

Answer:

$x^3-8$

Step-by-step explanation:

apply the inverse properties of logarithmic and exponential functions to simplify

$- 8 + e^{lnx^3}$

Inverse property of log says that

$e^{ln(x)=x$

we apply this property in our problem. ln has same base 'e' . so ln and e gets cancelled

$e^{ln(x^3)=x^3$

$- 8 + e^{lnx^3}$

$- 8 +x^3$

$x^3-8$

4 0

3 years ago

A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer

pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

$Z_{o.o5}$ = -1.648

You reverse the standardization using the formula $Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)$

$-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }$

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

$Z_{0.95}= 1.648$

$1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }$

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0

3 years ago

Read 2 more answers