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Elza [17]
3 years ago
8

Can someone help me with this equation please.Thank you!

Mathematics
2 answers:
lozanna [386]3 years ago
5 0
A(5,-3) quadrant II
Vesnalui [34]3 years ago
5 0

Answer:

Step-by-step explanation:

The point is A(5, -3) and the quadrant is IV

You might be interested in
Wats 10 to the 2nd power divied by 5 to the 2nd power
Ilya [14]

Answer:

4

Step-by-step explanation:

10^2/5^2

Do the exponents first

10 to the 2nd power is 100

5 to the 2nd power is 25

100/25

100 divided by 25 is 4

So the answer is 4

Hope this helps!

6 0
3 years ago
Fifteen students are going hiking on their spring break. They plan to travel in three vehicles—one seating 7, one seating 5, and
andriy [413]

Answer:

The students can group themselves in 360360 ways

Step-by-step explanation:

For this exercise we need to use the following equation:

\frac{n!}{n1!*n2!*...*nk!}

This equation give us the number of assignation of n elements in k cell, where n1, n2, ..nk are the element that are in every cell

In this case we have 15 student that need to be assign in three vehicles with an specific capacity. This vehicles would be the equivalent to cells, so we can write the equation as:

  \frac{15!}{7!*5!*3!}

Because the first vehicle have 7 seating, the second vehicle have 5 seating and the third vehicle have 3 seating.

Solving the equation we get 360360 ways to organized 15 students in three vehicles with capacity of 7, 5  and 3 seating.

5 0
3 years ago
One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
MaRussiya [10]

Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

5 0
3 years ago
Does someone mind helping me with this problem? Thank you!
Jet001 [13]

Answer:

875 ft²

Step-by-step explanation:

Finding area of similar rectangles:

Scale factor = EF : AB

                    = 25 : 5

                    = 5 : 1

\sf \dfrac{Area \ of \ bigger \ rectangle}{Area \ of \ smaller \ rectangle}= (Scale \ factor)^2

\dfrac{Area \ of \ bigger \  rectangle}{35} =\left(\dfrac{5}{1}\right)^2

\text{Area of bigger rectangle = $\dfrac{25}{1}*35$}

Area or rectangle EFGH = 875 ft²

4 0
2 years ago
Read 2 more answers
Chris answered 61 out of 66 questions correctly on a test. What is his test average to the nearest thousandth
mars1129 [50]
If you divide 61 by 66, you will get .9242424. The thousandths place is the third number, so you base it off of the four number. If the fourth number is under 5, the third number stays the same and all numbers after it disappear. If the number is above 5, the third number rounds up 1 and the rest disappear. Because the 3rd number is 4 and the 4th number is 2, you will get the answer of .924
4 0
3 years ago
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