Answer:
Simplifying
x2 + -4y2 = 25
Solving
x2 + -4y2 = 25
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4y2' to each side of the equation.
x2 + -4y2 + 4y2 = 25 + 4y2
Combine like terms: -4y2 + 4y2 = 0
x2 + 0 = 25 + 4y2
x2 = 25 + 4y2
Simplifying
x2 = 25 + 4y2
Reorder the terms:
-25 + x2 + -4y2 = 25 + 4y2 + -25 + -4y2
Reorder the terms:
-25 + x2 + -4y2 = 25 + -25 + 4y2 + -4y2
Combine like terms: 25 + -25 = 0
-25 + x2 + -4y2 = 0 + 4y2 + -4y2
-25 + x2 + -4y2 = 4y2 + -4y2
Combine like terms: 4y2 + -4y2 = 0
-25 + x2 + -4y2 = 0
The solution to this equation could not be determined.
Step-by-step sorry if im wrong
Y equals volume of water, x equals time. If they ask to find the coordinates at one minute, then the first thing you should do is set x equal to 1. That leaves two possible answers. Finally you need to decide how much water is lost in one minute. if you need more help leave a comment.
Answer:
Yes he is correct, If it was 100% then it would stay the same 10 hours. But since it's 110%, it is in fact 11.
Step-by-step explanation:
Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
