First make an equation representing this.

Y= total length
X= the distance from each wall

13 = 2x + 3.5

13 = 2x + 3.5

subtract 3.5 from each side

9.5 = 2x

Divide 2 from each side

X = 4.75 ft

6 0

3 years ago

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Given triangle ABC with angle ABC congruent to angle ACB, which step could be used to prove that side AB is congruent to side AC

arlik [135]

From A draw the altitude AH intersecting BC in H

Let's prove that triangle ABH is congruent to triangle ACH

The above 2 triangles are right triangles due to the altitude AH

Angle B= Angle C (given)
Angle AHB = Angle AHC =90° (since AH is the altitude)
Then angle BAH = CAH (both complementary to B & C respectively
And AH is a common side
Now Tri. ABH = Tri. ACH because ASA, hence AB=AC

4 0

4 years ago