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2 years ago

I need help on number 5

Mathematics

1 answer:

nikdorinn [45]2 years ago

3 0

A fraction is undefined if its denominator is zero, because then it's saying
"Division by zero !" which is a definite no-no.

Can the denominator of the fraction in #5 ever be zero ?

The denominator is a quadratic polynomial. Do you know
how to solve (a quadratic polynomial) = 0 ?

This problem is even easier than that, because it gives you some choices.
So you don't even have to solve the quadratic equation. All you have to do
is check out the choices.
Do you see choice of 'x' values that make the denominator zero ?

Big sloppy hint: Look at choice-E very very carefully.

Is that enough help ?

You might be interested in

Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.

Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0

3 years ago

To describe a specific arithmetic sequence, Elijah wrote the recursive formula:

11111nata11111 [884]

Answer:

$t_{n} = 30 + 7n$ , where, n = 0, 1, 2, 3, 4, .........

Step-by-step explanation:

Given the arithmetic sequence in recursive formula.

f(0) = 30 and f(n + 1) = f(n) + 7 ......... (1)

Therefore, putting n = 0 in equation (1) we get f(1) = f(0) + 7 = 30 + 7 = 37 {Since, f(0) is given to be 30}

Again, putting n = 1 in equation (1) we get f(2) = f(1) + 7 = 37 + 7 = 44

And, putting n = 2 in equation (1) we get f(3) = f(2) + 7 = 44 + 7 = 51

and so on.

Therefore, the arithmetic sequence is 30, 37, 44, 51, .......

Therefore, the linear equation of this sequence is given by $t_{n} = 30 + 7n$ , where, n = 0, 1, 2, 3, 4, .........

(Answer)

3 0

3 years ago

What value do you square to get 9?

Dominik [7]

Answer:

3 or -3

Step-by-step explanation:

What number multiplied by itself will give you 9

1*1 =1

2*2 =4

3*3 =9

Also note that negative times negative will be positive so

-1*-1=1

That means -3*-3 = 9

4 0

3 years ago

Read 2 more answers

14 and 15, please :p explanation would also be appreciated!!

liraira [26]

14. B (4, -2)
15. I am not exactly sure about this one but I would say either A or B.

8 0

3 years ago

What is 31,693 rounded to the nearest whole number?

Illusion [34]

Its about 32,000 rounded up

6 0

3 years ago