For
solving system of equations, we can use either substitution where we plug one
equation into the other, or elimination where we combine the equations.
-
Using elimination,
you would to eliminate one variable from both equations, so you automatically would
get one equation with one variable!
- Using
substitution
means you are going to solve one equation for one variable and substitute with
its value in the other equation in order to get also an equation with one
variable.
Let's take an example ...
y+x=2 and y-2x = 1
<span>Using <span>elimination, we need to subtract these two equation; one from the other...
y+x=2
-
y-2x=1
-----------
0+3x=1
then
x=1/3 and then substitute into any equation to get y-value</span></span>
y+x=2
y+1/3 = 2 >>>>>
y=5/3NOW...<span>Using substitution
</span>y+x=2 and y-2x = 1 >>(y=1+2x)
Plug (y=1+2x) into y+x=2 and solve for x
y+x=2
(1+2x) + x =2
1+3x = 2
3x=1
again (and for sure)
x = 1/3plug in x=1/3 into any of the equations above to get y:
y+x=2
y+1/3=2
y=5/3DOne !!!!!!
I hope you got
the idea
If you still need help, just let me know.
Answers:
- A) The equation is d = 2t
- B) Independent variable = time; dependent variable = amount of cookies
=========================================================
Explanation:
The independent variable is always long the horizontal axis. Often this is x, but we are using t in this case.
The variable t represents the amount of time in minutes. For instance, t = 2 means 2 minutes have elapsed. At this time, 4 cookies have been eaten as shown by the point (2,4). As another example, the point (3,6) means that d = 6 cookies have been eaten at time t = 3 minutes.
The equation is d = 2t because the '2' represents the rate of change of "eating 2 cookies per minute". Whatever the time value (t) is, we double it to get the value of d, which is the number of cookies eaten.
-15 so that is negative. so that is negative 15÷15 so 15 ÷15 is 1 so it would be -15÷-15=-1
Answer:
<u>brainliest plzzzzzzzz</u>
120
Step-by-step explanation:
LCM=1320
(GDC) HCF=12
Another no.=132
let second no. be =A
According to question
First no.×Second no.=HCF×LCM
132×A=12×1320
132×A=15840
A=15840/132
A=120
Other no. is 120
3 to the power of 5
you multiply 3 times 5 instead of 3 times 3 times 3 times 3 times 3
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