<em>So</em><em>,</em><em>the</em><em> </em><em>length </em><em>of</em><em> </em><em>rectangle </em><em>is</em><em> </em><em>2</em><em>4</em><em> </em><em>cm</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>The</em><em> </em><em>breadth</em><em> </em><em>of</em><em> </em><em>recta</em><em>ngle</em><em> </em><em>is</em><em> </em><em>1</em><em>8</em><em> </em><em>cm</em>
<em>please</em><em> </em><em>see</em><em> </em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> </em><em>full</em><em> </em><em>solution</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Answer:
The exact answer in terms of radicals is ![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)
The approximate answer is
(accurate to 5 decimal places)
===============================================
Work Shown:
Let ![y = \sqrt[5]{x^3}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B5%5D%7Bx%5E3%7D)
So the equation reduces to -7 = 8-3y
Let's solve for y
-7 = 8-3y
8-3y = -7
-3y = -7-8 ... subtract 8 from both sides
-3y = -15
y = -15/(-3) ... divide both sides by -3
y = 5
-----------
Since
and y = 5, this means we can equate the two expressions and solve for x

![\sqrt[5]{x^3} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%20%3D%205)
Raise both sides to the 5th power

Apply cube root to both sides
![x = \sqrt[3]{125*25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%2A25%7D)
![x = \sqrt[3]{125}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = \sqrt[3]{5^3}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B5%5E3%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)

The length of the line is the difference between the endpoints of the line
The length of each line to the nearest fourth inch is 0.25 inch
<h3>How to measure the length of each line</h3>
The length of the horizontal line is given as:
Length = 2 inches
This is calculated as:
Length = 3 inches - 1 inch
Length = 2 inches
8 lines are to be drawn between the 1 inch and 3 inches point.
So, the length (l) of each line is:

Simplify the fraction

Divide

Hence, the length of each line to the nearest fourth inch is 0.25 inch
Read more about line measurements at:
brainly.com/question/14366932
Word Problem:
Take a number, <em>x</em>, double it and then take that result away from 10.
Expression: