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Arlecino [84]
3 years ago
12

Steve collects oysters for a living and sells them to restaurants. While catching oysters, Steve keeps track of the total weight

of his bag of oysters. A graph of the total weight, in ounces, of Steve's bag of oysters, y, with respect to the amount of time that he spends looking for them in minutes, x, is shown below.
What is the average rate of change over the interval [2, 10]?

20 ounces of oysters per minute
8 ounces of oysters per minute
2 ounces of oysters per minute
10 ounces of oysters per minute
5 ounces of oysters per minute

Mathematics
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer:8 ounces of oysters per minute

Step-by-step explanation:

KiRa [710]3 years ago
5 0

Answer:

5 ounces of oysters per minute

Step-by-step explanation:

We are given a graph of the total weight, in ounces, of Steve's bag of oysters, y, with respect to the amount of time that he spends looking for them in minutes, x,

Now we are supposed to find the average rate of change over the interval [2, 10]

Formula of Average rate : \frac{f(x_2)-f(x_1)}{x_2-x_1}

Now At x = 2 , f(2)= y = 20

At x=10  , f(10)= y = 60

Substitute the values in the formula

Average rate : \frac{f(10)-f(2)}{10-2}

Average rate : \frac{60-20}{10-2}

Average rate : \frac{40}{8}

Average rate : 5

Thus he average rate of change over the interval [2, 10]  is 5 ounces of oysters per minute

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Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

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y = -15/(-3) ... divide both sides by -3

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-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

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