The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
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ABC ~ A’B’C’
So, AB=A’B’ , BC=B’C’ , AC = A’C’
Given, AB=15 and A’C’=4
So, AC = 4 , A’B’ = 15
The graph represented in the figure shows a set of linear equations each of which is represented a straight line.
Step-by-step explanation:
System of Equation can be referred to as an assortment of equations to be dealt with. Common examples include linear equations and non-linear equations such as a parabola, hyperbola etc.
Linear set of equations are the most simple of equation depicting a linear relationship between two variables.
E.g. Y=4x+3
here y and x share a linear relationship which is defined by the straight-line graph "4x+3"
Similarly in the graph lines, two straight lines are depicted which symbolises that the et of the equation is linear in character.