Problem #11:
Twice a number (n) decreased by 5 is at least 11.
2n - 5 is = to or greater than 11.
2n - 5 is = to 11 comes out as 2n = 11 + 5, or 2n = 16, or n = 8.
If n = 8 or is greater than 8, 2n=5 will be at least 11.
Please, start work on the problems you haven't yet done. I'd be happy to comment on your own work and help you bring the solution to conclusion.
Answer:1/9
Step-by-step explanation: divide both sides of the fraction by 2
Because every x value cannot have more than one y value so doing it will make sure it has only one value on the line.
Answer:
1/-21
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
17
4
x+
−1
12
=6x
Step 2: Subtract 6x from both sides.
17
4
x+
−1
12
−6x=6x−6x
−7
4
x+
−1
12
=0
Step 3: Add 1/12 to both sides.
−7
4
x+
−1
12
+
1
12
=0+
1
12
−7
4
x=
1
12
Step 4: Multiply both sides by 4/(-7).
(
4
−7
)*(
−7
4
x)=(
4
−7
)*(
1
12
)
x=
−1
21
Answer:
The new coordinate of B' will be ( -1, 6)
