Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9
balu736 [363]
Given:
The function is
To find:
The missing values for a, b, and c in the given table.
Solution:
We have,
At x=-2,
![\left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cleft%28%5Cdfrac%7Ba%7D%7Bb%7D%5Cright%29%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7Bb%7D%7Ba%7D%5Cright%29%5E%7Bn%7D%5Cright%5D)
At x=-1,
At x=0,
![\left[\because a^0=1, a\neq 0\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20a%5E0%3D1%2C%20a%5Cneq%200%5Cright%5D)
Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.
Step-by-step explanation:
The club would have to sell at least 6 t-shirts.
Answer:
Inequality:
120 + 0.05x ≥ 200
Solution:
x ≥ $1,600
Her total weekly sales must be equal to or greater than $1,600
Step-by-step explanation:
Let x represent the weekly sales she must make to reach her goal.
Given;
Pay rate = $8
Weekly total work hours = 15 hours
Commission on sales = 5% = 0.05
Total weekly earnings is;
8×15 + 0.05×x
120 + 0.05x
Minimum Weekly target earnings = $200
So;
120 + 0.05x ≥ 200
Solving the inequality equation;
0.05x ≥ 200 - 120
0.05x ≥ 80
x ≥ 80/0.05
x ≥ 1600
x ≥ $1,600
Her total weekly sales must be equal to or greater than $1,600
When adding fractions you need to get common denominators then you multiply too times bottom and then boom add and there you go
