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denis23 [38]
2 years ago
6

What is the distance between two points with coordinates at (8, 40) and (20, 5)?

Mathematics
1 answer:
Alchen [17]2 years ago
7 0

Answer:

37 units

Step-by-step explanation:

The two points form a right triangle so

a²+b²=c² so

(8-20)²(x values)+(40-5)²(y values)=c² (distance) so

12²+35²=c² so

144+1225=c²

1369=c²

c=37 units

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What is the equation of a line perpendicular to y= 3x +6 that crosses the ordered pair (3,2).
jasenka [17]

Answer:

y=-\frac{1}{3}x+3

Step-by-step explanation:

5 0
2 years ago
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57tan(27.32^0)

h\approx8.45 ft

Thus, the height of the statue is approximately, 8.45 feet.

3 0
3 years ago
What is an equation of the line that passes through the point (1,6) and is perpendicular to the line x+3y=27
nadezda [96]

Answer:Which of the following is true about fiber in foods?

Group of answer choices

it is not digested

it helps one's muscles grow weaker

it is always thin and threadlike

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Step-by-step explanation:

5 0
3 years ago
(-8) - 3y= 25<br><br>if you have time please help, thank you​
Neko [114]

(-8) - 3y= 25

-8-3y= 25

move -8 to the other side

sign changes from -8 to +8

-8+8-3y=25+8

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divide both sides by -3 to get y by itself

and to get +y

-3y/-3= 33/-3

Answer:

y= -11

8 0
2 years ago
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