Answer:
A, B, C
Step-by-step explanation:
Assuming the choices are:
A. 
B. 
C. A+
D. 
Put simply, a polynomial in this case will be a function that has at least one variable raised to a power greater than 1.
Choice A already has a variable raised to a power greater than 1 (
), so no additional manipulation is needed.
Choice B also has a term that is already raised to a power greater than 1 (
). It is the same for choice C (
).
Choice D does not have an obvious variable raised to a power greater than 1. When the equation is manipulated it becomes
. Since -1 is less than 1, choice D is not a polynomial.