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Katyanochek1 [597]
3 years ago
9

Write 4 x 3,569 in expanded form to show the place value of each digit. Then find the product.

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
The answer would be 14,276
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Two solutions of the equation Ax+By = 1 are (2, -1) and (-3,-2). Find A and B.
kati45 [8]

Answer:

Substitute in the values of both given coordinates & form 2 equations:

\left \{ {{A(2)+B(-1)=1} \atop {A(-3)+B(-2)=1}} \right. \\\\=\left \{ {{2A-B=1} \atop {-3A-2B=1}} \right.

Find the value of B from the equation 2A - B = 1:

2A-B=1\\-B=1-2A\\B=2A-1

Substitute in the B-value to the other equation:

-3A-2B=1\\-3A-2(2A-1)=1\\-3A-4A+2=1\\-7A=1-2\\-7A=-1\\A=\frac{-1}{-7} =\frac{1}{7}

Find the B-value using the equation from before:

B=2A-1=2(\frac{1}{7})-1=\frac{2}{7} -\frac{7}{7} =-\frac{5}{7}  

Therefore the equation Ax + By = 1 would equal:

\frac{1}{7} x-\frac{5}{7} y=1

4 0
3 years ago
X to the power of 2 plus Y to the power of 2 plus 4x-2y=1
exis [7]

Answer:

sfddddddgfd

Step-by-step explanation:

6 0
3 years ago
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HELP! I NEED THIS ANSWER, WILL GIVE BRAINLIEST
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Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBBBB

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4 years ago
75/12=□/4=160/□what is the answer?<br><br><br><br><br>​
Vlada [557]

Answer:

75/12= 6.25/4=160/102.4

4 0
3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
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