Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :
H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
Answer:
4.5
Step-by-step explanation:
1/2 times base times height
( Area of a triangle )
1/2(3)(3)
=4.5
Answer:
it's the 2nd one
Step-by-step explanation:
hoped I helped:)
Answer:
#6 is 17 days
Step-by-step explanation:
This is how I answered it
1) 2750 = 550 + 125x
2) subtract 550 from each side
2750-550=2200
so the left over equation is:
2200 = 125x
3) divide each side by 125 to get x by itself
2200÷125= 17.6
4) you are left with: x = 17 days
Answer:
x = 9
Step-by-step explanation:
x−(3)(3=x+−9 )
