You are given Maggie's planning on going to Penn State University. You are also given that she could live there if she has more than $2,000 if she already bought a laptop at $450.
For part A, the inequality that we can form is x ≥ 2,450 because she needs more than $2,000 to survive after buying a $450 dollar worth laptop. Adding the two makes it 2,450.
For part B, if she has to withdraw $30 per week, then the inequality that we can form is x ≥ 2,450 - 30
For part C,
30x ≥ 2,000
x ≥ 66.67
For part D, the answer 66.67 means that Maggie can have 66 times to withdraw $30 per week worth of food from her balance $2000.
,,,,,,,,,,,,,,,,,i want the answer
marysya [2.9K]
Answer:
120 Degrees
Step-by-step explanation:
As the set up says the two angles (m<A and m<C) are the same so you would simply just divide 240 by 2 (240/2) to find your answer of 120.
All the place values of 12, 354.897 are as follows: 12 thousands, 3
hundred, 5 tens, 4 ones, 0.8 tenths .09 hundredths, .007 thousandths.
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
