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Molodets [167]
2 years ago
8

What is the value of x? Enter your answer in the box. _____ units

Mathematics
2 answers:
krek1111 [17]2 years ago
6 0

Answer:

x=28

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem.  Put the side of the small triangle over the same side of the larger triangle.

x               42

---------- = ----------

x+10           42+15

Simplify

x               42

---------- = ----------

x+10           57

Using cross products

57x = 42 (x+10)

Distribute

57x = 42x+420

Subtract 42x from each side

57x-42x = 42x-42x +420

15x = 420

Divide each side by 15

15x/15 = 420/15

x=28

MariettaO [177]2 years ago
5 0

Answer: The value of x is 28 units.

Step-by-step explanation:

Since we have given that

DC ║ PA

So, By Basic Proportionate theorem, if a line drawn parallel to the third side and intersect the other two sides, then the other two sides are divided into same ratio.

So, it becomes,

\frac{RC}{CA}=\frac{RD}{DP}\\\\\frac{x}{10}=\frac{42}{15}\\\\15\times x=10\times 42\\\\x=\frac{420}{15}=28\\\\x=28

Hence, the value of x is 28 units.

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Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

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\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
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So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
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