<span>Martin deposits $200
in a savings account that earns 5% annual interest.
year interest balance
1 200 * 5% 200(1.05)
2 200(1.05) * 5% 200(1.05)^2
3 200(1.05)^2*5% 200(1.05)^3
y 200(1.05)^y
=> m = 200 (1.05)^y
four years later,
cary deposits $200 in an account earning the same interest.
</span>
<span><span>year interest balance
5 200 * 5% 200(1.05)
6 200(1.05) * 5% 200(1.05)^2
7 200(1.05)^2*5% 200(1.05)^3
y 200(1.05)^(y-4)
=> c = 200(1.05)^ (y-4)
</span>
Answer:
Martin: 200(1.05)^y
Cary: 200(1.05)^(y–4)</span>
Hopefully this helps you ..
Answer:
Step-by-step explanation:
We have been given that that there are 8 boys from Wilmette, 5 girls from Kenilworth, 9 girls from Wilmette, 5 boys from Glencoe, 5 boys from Kenilworth and 7 girls from Glenoce.
The total number of students from Kenilworth is 5 boys plus 5 girls that is 10 students.
The total number of students in the class would be 
Therefore, the probability, that the student will be from Kenilworth, is approximately 0.256.
Answer:
14
Step-by-step explanation:
When you plug this expression into the calc, you should get 14 as your answer.
