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zavuch27 [327]
3 years ago
13

A pro baseball team is having a promotion in which every 10th fan that enters the stadium gets a free hat and every 12th person

gets a free T-shirt .
How many fans Will come into the stadium before a fan receives both a hat and a T- shirt ?
Mathematics
1 answer:
mixas84 [53]3 years ago
3 0
Multiples of 10 = 10, 20, 30, 40, 50, 60
This means the 10th, 20th, 30th, 40th, 50th, 60th, ... fan will get a free hat.
Multiples of 12 = 12, 24, 36, 48, 60
This means the 12th, 24th, 36th, 48th, 60th, ... fan will get a free shirt.
So the 60th fan will receive both a hat and a shirt.
Meaning 60 fans will come to the stadium before a fan receives both a hat and a shirt.
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Yes I can help you with rational expressions and eplquations!
4 0
3 years ago
Use the cosine ratio or the inverse cosine to solve for x. Round your answer to the nearest tenth.
maria [59]

Answer:

x ≈ 12.6 m

Step-by-step explanation:

By using cosine ratio in the given right triangle RTS,

cos(S)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(33)° = \frac{\text{ST}}{\text{SR}}

cos(33)° = \frac{x}{15}

x = 15.cos(33)°

x = 12.58

x ≈ 12.6 m

Therefore, measure of side ST = 12.6 m is the answer.

7 0
3 years ago
The area of a parallelogram is 400m2 the base is 25m find the length of the height
icang [17]
HEIGHT=6400 DUE TO THE FACT THAT U ARE MULTIPLYING 400 TWICE, THEN DIVIDING BY 25.
5 0
4 years ago
The product of two irrational numbers is. Rational
Snowcat [4.5K]

Answer:

So the statement:

"The product of two irrational numbers is rational." is false.

Step-by-step explanation:

The product of two irrationals can be irrational or rational.

Example:

\sqrt{2} \cdot \sqrt{2}=2

\sqrt{2} is irrational but when you multiply it to itself the output is rational.

Example:

\sqrt{2} \cdot \sqrt{3}=\sqrt{6}

\sqrt{2} \text{ and } \sqrt{3} are irrational and when you multiply them you get an irrational answer of \sqrt{6}.

So the statement:

"The product of two irrational numbers is rational." is false.

5 0
3 years ago
There are 130 people in a sport centre.
Mashcka [7]

Answer:

<h2>7/130</h2>

Step-by-step explanation:

Using set notation to answer the question. let:

n(U) be the total people in a sport centre =130

n(G) be number of people that use the gym.  = 76

n(P) be number of people that use the swimming pool. = 60

n(T) be number of people that use the track = 32

n(G∩P) be number of people that uses the gym and the pool = 23

n(P∩T) be number of people that uses the  pool and the track = 8

n(G∩T) be number of people that uses the gym and the track = 320

n(G∩P∩T) be number of people that uses all three facilities = 6

Using the relationship below;

n(U)= n(GUPUT)+n(GUPUT)'

where n(GUPUT)' is the number of people that doesn't use any facility.

Before we can get that, we need to know n(GUPUT) using the formula;

n(GUPUT) = n(G) + n(P)+n(T)-n(G∩P)-n(P∩T)-n(G∩T)+n(G∩P∩T)

n(GUPUT) = 76+60+32-23-8-20+6

n(GUPUT) = 123

n(GUPUT)' = n(U)- n(GUPUT)

n(GUPUT)' = 130 - 123

n(GUPUT)' = 7

This means that 7 person doesn't use any facility.

Probability that a person selected at random doesn't use any facility = n(GUPUT)' /n(U) = 7/130

3 0
3 years ago
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