Question

For what values of k will the function y=6x^2-8x+k have one zero: Two zeros: No zeros

Answer 1

Answer:

Step-by-step explanation:

consider 6x^2-8x +k

disc .=(-8)^2-4*6*k=64-24k

it has no solution if 64-2k<0

or 64<2k

or 2k>64

k>32

it has two zeros if 64-2k≥0

or 64≥ 2k

or 2k≤64

or k≤ 32

it has one zero if Disc. =0

64-2k=0

2k=64

k=32