They are counting by twos.
2,4,6,8,10,12,14,16,18,20,etc
Answer:
B
Step-by-step explanation:
I’m not rlly sure if i did it right & i’m sorry if i didn’t. i used the FOIL method
f= first to first
o=outer to outer
i=inner to inner
l= last to last
so it’d be
8b + 6b = 14b (f)
8b+ 8=16b(o)
-7+6b=-1b(i)
-7+8(l)
and then you add like terms so
[14b+16b-1b]+1
= 29b+1
Answer:
5√3 ft/s
Step-by-step explanation:
Let h represent the horizontal distance of the kite from the person. Let s represent the string length. Then the Pythagorean theorem tells us ...
s^2 = 100^2 + h^2
2s·ds/dt = 0 + 2h·dh/dt
ds/dt = (h/s)·dh/dt
So, we need to know the horizontal distance when s=200.
200^2 = 100^2 + h^2
40000 -10000 = h^2
h = 100√3
Substituting known values into the equation for ds/dt, we have ...
ds/dt = (100√3)/(200)(10 ft/s) = 5√3 ft/s
The string must be let out at 5√3 ft/s when it is already 200 ft long.
Answer:
27, 15, 13
Step-by-step explanation:
