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Roman55 [17]
3 years ago
13

What could the formula 2a + 2b represent?

Mathematics
2 answers:
sattari [20]3 years ago
6 0
Becaus you have 2A and 2b this is what i think it could mean A+A+B+B
wolverine [178]3 years ago
5 0
The answer could be 2(a+b)
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Find the distance between the points (3, –8) and (0, –9).
nadezda [96]

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =0\\x_{1} =3\\y_{2} =-9\\y_{1} =-8

^^^Plug these numbers into the formula for distance like so...

\sqrt{(0-3)^{2} + (-9 - (-8))^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(0-3)^{2} + (-9-(-8))^{2}}

0 - 3 = -3

\sqrt{(-3)^{2} + (-9-(-8))^{2}}

-9 - (-8) = -1

\sqrt{(-3)^{2} + (-1)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(-3)^{2} + (-1)^{2}}

(-3)² = 9

\sqrt{9 + (-1)^{2}}

(-1)² = 1

\sqrt{(9+1)}

Now for the addition

\sqrt{(9+1)}

9 + 1 = 10

√10 <<<This can not be further simplified so this is your exact answer

Your approximate answer would be about 3.16

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
In the rational expression,
Travka [436]

Answer:

The reason why it is incorrect to cancel the 4x in the numerator with the 4x in the denominator is because 4x is not a factor of both the numerator and the denominator

Step-by-step explanation:

The denominator of the rational expression, x^2 + 4x - 12 given above is a quadratic equation. It is not factorizable. If we factorize the numerator, 4x - 8, we would have

4 (x - 2).

This means 4x is not a factor of the numerator(4x - 8) and neither is it a factor of the denominator (x^2 + 4x - 12). This is the reason why it is incorrect to cancel the 4x in the numerator with the 4x in the denominator. The factors of the denominator can only be gotten by using the general formula for solving quadratic equations

3 0
3 years ago
Which is greater 10.2 or 10
Effectus [21]
10.2 is greater because 10.2 is 10+.2 whereas 10 is just 10
10.2 has that .2  which makes it greater than 10
7 0
3 years ago
Read 2 more answers
Please give me the answer and explanation .
Hunter-Best [27]

Answer:

What is the question though?? Pls send an attachment on an new question :))

Step-by-step explanation:

7 0
3 years ago
Find the three angles of the triangle with the given vertices: P(1,1,1), ????(1,−3,2), and ????(−3,2,5).
velikii [3]

Answer:

The three angles of the triangle are 90, 35.67 and 54.33 degrees.

Step-by-step explanation:

One way to find the angles of the triangle with vertices (1, 1, 1), (1, -3, 2), (-3, 2, 5) is using the definition of the <em>dot product</em> of two vectors, defined as:

a . b = |a| |b| cosФ [1]

Where |a| and |b| are the norms of vectors <em>a</em> and b, and cosФ is the cosine of the angle between either vector <em>a</em> and <em>b</em>.

If a = [ \\ a_{1}, a_{2}, a_{3} ] and b = [\\ b_{1}, b_{2}, b_{3}], then the dot product is simply a number (not a vector) obtained from:

a . b = \\ a_{1}*b_{1} + a_{2}*b_{2} + a_{3}*b_{3}

The norm of a vector (its length) is, for instance, |a| = \\ \sqrt{{a_{1}^2 + {a_{2}}^2 + {a_{3}}^2}, for a vector in \\ R^{3}.

Having all that into account, we can determine the angles of the triangle for each vertex using equation [1] and solving it for Ф.

<h3>Angle of the triangle for vertex in (1, 1, 1)</h3>

The vectors which form an angle from this vertex are the result of subtracting the vertex (1, 1, 1) to any of the remaining points (1, -3, 2) and (-3, 2, 5):

v(1, 1, 1) - v(1, -3, 2) = \\ (1 - 1, 1 - (-3), 1 - 2) = (0, 1 + 3, -1) = (0, 4, -1)

v(1, 1, 1) - v(-3, 2, 5) = \\ (1 - (-3), 1 - 2, 1 - 5) = (1 + 3, -1, -4) = (4, -1, -4)

The <em>dot product</em> for these vectors is:

[0, 4, -1] . [4, -1, -4] = [0 * 4 + 4 * -1 + -1 * -4] = 0 - 4 + 4 = 0

The norm for each vector is:

|(0, 4, -1)| = \\ \sqrt{0^2 + 4^2 + -1^2} = \sqrt{0 + 16 + 1} = \sqrt{17}

|(4, -1, -4)| = \\ \sqrt{4^2 + -1^2 + -4^2} = \sqrt{16 + 1 + 16} = \sqrt{33}

So

a . b = |a| |b| cosФ

\\ 0 = \sqrt{17} * \sqrt{33} * cos{\theta}

\\ \frac{0}{\sqrt{17} * \sqrt{33}} = cos{\theta}

\\ cos^{-1}{0}} = cos^{-1}(cos{\theta})

\\ 90 = \theta

In vertex (1, 1, 1) the angle of the triangle is 90 degrees. We have here a right triangle.

We have to follow the same procedure for finding the vectors for angles in vertices (1, -3, 2) and (-3, 2, 5), or better, after finding one of the previous angles, we find the remaining angle subtracting the sum of two angles from 180 degrees to finally obtaining the three angles in question.

Therefore, the other angles are 35.67 degrees and 180 - (90 + 35.67) = 180 - 125.67 = 54.33 degrees.

5 0
3 years ago
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