Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft
Radical 15 is an irrational number
The 1 is in the ten thousands place
Answer:

Step-by-step explanation:
Given
--- probability of scoring
Required
Probability that his first miss is his 6th shot
Let q represent the event that he did not score.
Using complement rule:

The event that his first miss is his 6th is represented as:
p p p p p q ---- That he scoress the first 5 attempts
So, the probability is:

