All categories

2 years ago

I need help with this question

Mathematics

1 answer:

Damm [24]2 years ago

8 0

3 hours

The first car would travel 180 miles in 4 hours.
The second car would travel 180 miles in 3 hours.

You might be interested in

(6,-2) and a slope of 4/3 in point slope form

Rufina [12.5K]

Answer: y=4/3x-10

Step-by-step explanation: Find the equation using Point-Slope formula.

Hope this helps you out! ☺

7 0

2 years ago

What does positive correlation mean?

valina [46]

Answer:A positive correlation is a relationship between two variables such that their values increase or decrease together.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Do the points lie on the same line? Explain your answer.

Anna007 [38]

A, sorry if I am wrong.

8 0

2 years ago

The difference of 9 and the square of a number. answer it right please

madam [21]

Answer:

let the number be x .

$9 - x ^{2}$

6 0

2 years ago

Uhm mainly 11 and 12 but if u solve all of them I’ll give u brainliest

Dvinal [7]

Question 11)

Answer:

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80$

Step-by-step explanation:

Given the expression

$\log _2\left(63\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)$

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(\frac{63}{9}\right)$

$=\log _2\left(\frac{63}{9}\right)$

$\mathrm{Divide\:the\:numbers:}\:\frac{63}{9}=7$

$=\log _2\left(7\right)$

$=2.80$

Therefore,

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80$

Question 12)

Answer:

$\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32$

Step-by-step explanation:

Given the expression

$\log _2\left(3\right)+\log _2\left(15\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)$

$\log _2\left(3\right)+\log _2\left(15\right)=\log _2\left(3\cdot \:15\right)$

$=\log _2\left(3\cdot \:15\right)-\log _2\left(9\right)$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:15=45$

$=\log _2\left(45\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)$

$\log _2\left(45\right)-\log _2\left(9\right)=\log _2\left(\frac{45}{9}\right)$

$=\log _2\left(\frac{45}{9}\right)$

$\mathrm{Divide\:the\:numbers:}\:\frac{45}{9}=5$

$=\log _2\left(5\right)$

$=2.32$

Therefore,

$\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32$

3 0

2 years ago