we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
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Answer:
just look at the decimal after the decimal number is the tenths place the hundreds place and so on if i have to round 567.1092 i would round the nine up to make the zero a one so my rounded answer would be 567.11
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
The general equation of a quadratic function in factored form is equal to
where
a is a coefficient of the leading term
x_1 and x_2 are the roots
we have
substitute
Applying the distributive property convert to expanded form
therefore
The '4' marked in the cut-out must be its width, because it can't be the height ... the height of the cut-out must be 3. / / / The area of the entire big rectangle is 12 x 14 = 168. The area of the little cut-out is 4 x 3 = 12. The area left is 168 - 12 = 154 ./ / / By the way ... if you're not getting many answers, it's because your drawings are unreadable. Put away the big orange marker and use a ballpoint pen instead.
You are not giving enough information but in one of the calsses the average of student's height might be greater than the other class beacause one of the two classes needs to have 1 extra person than the other calss
