The probability that a randomly selected chocolate bar will have between 200 and 220 calories is 3.97%
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
The zscore is given a:
z = (raw score - mean) / standard deviation
mean = 225, standard deviation o = 10.
a) For x = 200:
z = (200 - 225) / 200 = -0.125
For x = 220:
z = (220 - 225) / 200 = -0.025
P(-0.125 < z < -0.025) = P(z < -0.025) - P(z < -0.125) = 0.4880 - 0.4483 = 3.97%
b) For x = 190:
z = (190 - 225) / 200 = -0.175
P(z < -0.025) = P(z < -0.175) = 0.4286
The probability that a randomly selected chocolate bar will have between 200 and 220 calories is 3.97%
Find out more on equation at: brainly.com/question/2972832
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Answer:
The measure of the arc PJ is 
Step-by-step explanation:
step 1
Find the measure of angle L
we know that
In a inscribed quadrilateral opposite angles are supplementary
so

we have

substitute


step 2
Find the measure of arc KJ
we know that
The inscribed angle measures half that of the arc comprising
so

substitute the values



step 3
Find the measure of arc PJ
we know that
The inscribed angle measures half that of the arc comprising
so

substitute the values



Answer:
that's my answer
Step-by-step explanation:
i hope it helps
Answer:
Domain (-2,3)
Range (-10, 20)
Function: Definitely
Step-by-step explanation: So check it right. Starting with Domain how far do our values go in the x direction positive and negative in this case the farthest to the left is -2 and to the right is 3. For range same thing but now we look at the y axis -10 is lowest and 20 is the highest. Open circles don't affect our domains or range but they are important for determining functions. This is a function because going up and down the graph vertically at any points doesn't collide with any point more than once. If the open circle were closed then this would not be a function but in this case it is a function.