i'm not sure how to solve the first one but the second is 150
Answer:
Step-by-step explanation:
Use the Law of Cosines
A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
