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Paladinen [302]

3 years ago

11

I need help with this question.

1 answer:

Kitty [74]3 years ago

4 0

i'm not sure how to solve the first one but the second is 150

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(3, 5) and (-1, -2) in slope-intercept form

stepladder [879]

Answer: y=7/4x - 1/4
Explanation:

8 0

4 years ago

What are x and y plsss helppppp

amid [387]

The y-intercept is the point where the line crosses the Y-axis. And the X-intercept is where a line crosses the X-axis

4 0

3 years ago

To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equati

Ad libitum [116K]

Answer:

$m = \frac{1}{12}$

Step-by-step explanation:

Given

$(x,y) = (36,6)$

$f(x) = \sqrt x$ ----- the equation of the curve

Required

The slope of f(x)

The slope (m) is calculated using:

$m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}$

$(x,y) = (36,6)$ implies that:

$a = 36; f(a) = 6$

So, we have:

$m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}$

$m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}$

If $f(x) = \sqrt x$ ; then:

$f(36 + h) = \sqrt{36 + h}$

So, we have:

$m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}$

Multiply by: $\sqrt{36 + h} + 6$

$m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}$

Expand the numerator

$m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}$

Collect like terms

$m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}$

$m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}$

Cancel out h

$m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}$

$h \to 0$ implies that we substitute 0 for h;

So, we have:

$m = \frac{1}{\sqrt{36 + 0} + 6}$

$m = \frac{1}{\sqrt{36} + 6}$

$m = \frac{1}{6 + 6}$

$m = \frac{1}{12}$

<em>Hence, the slope is 1/12</em>

7 0

3 years ago

Mrs Omar runs the school tennis club. She has a bin of tennis balls and rackets for every 5 tennis balls in the bin there are 5

irakobra [83]

Answer:

x=y

Step-by-step explanation:

-let x be the number of tennis balls and y the number of rackets.

-We divide the number of balls by the number of rackets to find out their ratio of proportionality:

$\frac{x}{y}=\frac{5}{5}=\frac{1}{1}\\\\\\=>x:y$

-Hence, for each one tennis ball, there is a tennis racket.

#This is a direct linear relationship and is modeled as graphed in the attachment:

4 0

3 years ago

Quadrilateral ABCD is inscribed in this circle. What is the measure of ∠A ?

Sonja [21]

Angles A and C are supplementary when the quadrilateral is inscribed in a circle.
∠A = 180° - ∠C
∠A = 180° - 74° = 106°

5 0

3 years ago