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Otrada [13]
3 years ago
7

Ms kashipour gave the class 12 min to read . Carrie reads 51/2 pages in that time . At what rate in pages per hour did Carrie re

ad
Mathematics
1 answer:
lianna [129]3 years ago
5 0

Her rate of reading was = 51/2 /12 = 51/24 per hour

It means she red 51/24 pages in one hour

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What is the reference angle of 255°?​
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255 degrees is in quadrant 3. The reference angle in this case is the negative x axis to 255 degrees, which is 255 - 180 = 75 degrees

Step-by-step explanation:

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Two sides of a triangle measure 9 cm and 23 cm. Which could be the measure of the third side of the triangle?
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9 because most of the triangle have to sides of the same sizes

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4 years ago
A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If the
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Answer:

<u>The area of the rectangular field is 20,000 square meters.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of times a person jogged along the rectangular field = 10

Speed of the person jogging = 12 km per hour

Time he/she jogged = 30 minutes = 0.5 hours

Length of the field = twice its width

2. Find the area of the field in square meters.

Step A: Let's calculate the distance the person jogged

Let's recall the formula of the speed:

Speed = Distance/Time

Distance = Speed * Time

Replacing with the values we know:

Distance = 12 * 0.5

<u>Distance = 6 kilometers</u>

Step B: Let's calculate the perimeter of the rectangular field

Distance jogged = ¨Perimeter * 10

6 kilometers = Perimeter * 10

Perimeter = 6/10

<u>Perimeter = 0.6 kilometers = 0.6 * 1,000 = 600 meters</u>

Perimeter = 2 * Length + 2 * Width

x = Width of the rectangular field

2x = Length of the rectangular field

600 = 2 * 2x + 2 * x

600 = 4x + 2x

600 = 6x

<u>x = 600/6 = 100 meters ⇒ 2x = 200 meters</u>

Step C: Let's calculate the area of the rectangular field

Let's recall the formula of the area of a rectangle:

A = Length * Width

A = 200 * 100

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7 0
4 years ago
Suppose a 2011 Gallup poll revealed that 76% of Americans believe that high achieving students should be recruited to become tea
k0ka [10]

Answer:

95% Confidence interval:  (0.73,0.79)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1021

Percentage of Americans believe that high achieving students should be recruited to become teachers

\hat{p} = 76\% = 0.76

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.76\pm 1.96(\sqrt{\dfrac{0.76(1-0.76)}{1021}})\\\\ = 0.76\pm 0.0261\\=(0.7339,0.7861)\\\approx (0.73,0.79)  

5 0
3 years ago
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