What is the solution to this system of equation?
1 answer:
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Answer:
The coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
Step-by-step explanation:
<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>
We are given a trapezoid such that the vertices of trapezoid are:
E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)
Then the new coordinates after the given transformation is:
E(-4,8) → E'(-8,-4)
F(-7,5) → F'(-5,-7)
G(-4,3) → G'(-3,-4)
H(-2,5) → H'(-5,-2)
Hence the coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
Answer: (a) y = -3x + 10
<u>Step-by-step explanation:</u>
The slope of line CD is perpendicular to line OB, which means they have opposite and reciprocal slopes.
Step 1: Find the slope of OB using the formula:
(x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 1)
Step 2: Find the slope of CD (opposite and reciprocal of OB)
Step 3: Input the perpendicular slope and the slope into the Point-Slope formula: y - y₁ = m(x - x₁)
(x₁, y₁) = (3, 1) because it is the point the line will pass through
y - 1 = -3(x - 3)
y - 1 = -3x + 9 <em>distributed -3 into (x - 3)</em>
y = -3x + 10 <em>added 1 to both sides</em>
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The x-intercept of DQ is the same x-intercept as CD. The x-intercept is when y = 0
y = -3x + 10
0 = -3x + 10
-10 = -3x subtracted 10 from both sides
<em>divided both sides by -3</em>
Answer:
The roots are
<h3>Step-by-step explanation:
9x² + 54x + 82 = 0
Using the quadratic formula
That's
<h3>From the question
a = 9 , b = 54 , c = 82
Substitute the values into the above formula and solve
That's
<h3>Separate the real and imaginary parts
That's
<h3>We have the final answer as
<h3>Hope this helps you