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STALIN [3.7K]
3 years ago
12

What is the surface area of a rectangle if the length is 4 1/5 the width is 9 1/2 and the height is 3 4/5?

Mathematics
1 answer:
ipn [44]3 years ago
3 0
Are there any answer choices
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The space inside a circle is the _ of the circle.
n200080 [17]

Answer:

The space inside a circle is the area of the circle.

The border of the circle is the circumference of the circle.

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3 years ago
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Suppose that a random sample of size 10 from the N(µ, 9) distribution resulted in a sample mean of x = 2.7. Give an 85% condiden
stellarik [79]

Answer:

a) CI: 1.3

b) CI: 2.5

c) CI: 2.0

Step-by-step explanation:

a) We have a sample of size n=10 and a sample mean of x=2.7.

The σ² of the population is known and is σ²=9 or σ=3.

For a CI of 85%, the z-value is 1.44.

Then the lower and upper limits of the CI are:

LL=M-z*\frac{\sigma}{\sqrt{n} } =2.7-1.44*\frac{3}{\sqrt{10} }=2.7-1.44*\frac{3}{3.162} =2.7-1.4=1.3\\\\UL=M+z*\frac{\sigma}{\sqrt{n} } =2.7+1.4=4.1

The 85% confidence interval for the mean is defined by the values LL=1.3 and UL=4.1.

CI: 1.3

b) In this case, the variance of the population is unknown.

We have to estimate the variance of the population from the variance of the sample.

Sample data:

n = 100

x(mean) = 2.7

s² = 1.1

The CI is defined as

x-t*\frac{s}{\sqrt{n} }

The value of t depends of the degrees of freedom and the percentage of confidence.

In this case, the degrees of freedom are n-1=100-1=99 and the CI is of 90%.

We look up in a t-table and the t-value for this conditions is 1.6604.

We can now calculate the CI

LL: x-t*\frac{s}{\sqrt{n} }=2.7-1.6604*\frac{\sqrt{1.1} }{\sqrt{100} } =2.7-0.2=2.5\\\\UL: x+t*\frac{s}{\sqrt{n} }=2.7+0.2=2.9

The 90% confidence interval for the mean is defined by the values LL=2.5 and UL=2.9.

CI: 2.5

c) In this case, the variance of the population is unknown.

We have to estimate the variance of the population from the variance of the sample.

Sample data:

n = 10

x(mean) = 2.7

s² = 1.1

The CI is defined as

x-t*\frac{s}{\sqrt{n} }

The value of t depends of the degrees of freedom and the percentage of confidence.

In this case, the degrees of freedom are n-1=10-1=9 and the CI is of 95%.

We look up in a t-table and the t-value for this conditions is 2.2622.

We can now calculate the CI

LL: x-t*\frac{s}{\sqrt{n} }=2.7-2.2622*\frac{\sqrt{1.1} }{\sqrt{10} } =2.7-0.7=2.0\\\\UL: x+t*\frac{s}{\sqrt{n} }=2.7+0.7=3.4

The 95% confidence interval for the mean is defined by the values LL=2.0 and UL=3.4.

CI: 2.0

5 0
3 years ago
There are 132 projects in the science fair. if 8 projects can fit in a row, how many full rows of the projects can be made? how
wel
Divide 132 by 8. You will get the quotient of 16 and the remainder of 4. So each row has 16 projects. The remaining 4 projects cannot be filled completely in a row.
4 0
3 years ago
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What is the least common denominator (LCD) for these fractions?
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The least common denominator (LCD) for 1/12 and 3/4 is b. 12
8 0
3 years ago
FREEEEEEE POIIIIIIIIINTS!!!!!!!!!!!!!!!!!!!!!!!!!
Travka [436]

Answer: thank you

Step-by-step explanation: have a good day :)

7 0
3 years ago
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