Which is a common disease involving the sores on the esophagus, stomach, and/or small intestine?

Explain how a ship made of materials that are much denser than water is able to float on water?

Helen [10]

It is because the weight is equal to each other and balances out. example war ships have tons of metal, but it spreads the weight on the water

7 0

4 years ago

Despite their name, standing waves actually do cause the medium to move

Gemiola [76]

Answer:

true

Explanation:

5 0

3 years ago

If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in

Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, $N_P$ = 50 turns

number of turns in the secondary winding, $N_S$ = 10 turns

the secondary load resistance, $R_S$ = 250 Ω

Determine the turns ratio;

$K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5$

Now, determine the reflected resistance in the primary winding;

$\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms$

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0

3 years ago

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v' = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V' = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0

4 years ago

I’m confused on the simplest part, which is what to multiply the 2/5 by to get it to the other side...please help

san4es73 [151]

Answer:

Mass, M = 4.859 Kg

Explanation:

Given the following data;

Radius, r = 0.225 m

Moment of inertia, I = 0.123 kgm²

To find the mass;

Mathematically, the moment of inertia is given by the formula;

I = ⅖Mr²

Making M the subject of formula, we have;

Cross-multiplying, we have;

2I = Mr²

$M = \frac {2I}{r^{2}}$

Substituting into the formula, we have;

$M = \frac {2*0.123}{0.225^{2}}$

$M = \frac {0.246}{0.050625}$

Mass, M = 4.859 Kg

7 0

3 years ago