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In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.
Let's consider the balanced equation for the reaction between 1 molecule of bromine and 2 molecules of potassium chloride. This is a single replacement reaction.
Br₂ + 2 KCl ⇒ 2 KBr + Cl₂
We obtain as products, 2 molecules of potassium bromide and 1 molecule of chlorine.
- 1 molecule of KBr has 2 atoms, so 2 molecules contribute with 4 atoms.
- 1 molecule of Cl₂ has 2 atoms.
- The 4 atoms from KBr and the 2 atoms from Cl₂ make a total of 6 atoms.
In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.
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Answer:
T= 38.38 N
Explanation:
Here
mass of can = m = 3 kg
g= 9.8 m/sec2
angle θ = 40°
From figure we see the vertical and horizontal component of tension force T
If the can is to slip - then horizontal component of tension force should become equal to force of friction.
First we find force of friction
Fs= μ R
where
μ = 0.76
R = weight of can = mg = 3 × 9.8 = 29.4 N
Now horizontal component of tension
Tx= T cos 40 = T× 0.7660 N
==>T× 0.7660 = 29.4
==> T= 38.38 N
Answer:
0.015 m/s2
Explanation:
Using Newtons 2nd law.
F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.
So substitute the values in SI units.
m = kg
Therefore F = 0.003×5 = 0.015 m/s2