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Gwar [14]
3 years ago
13

PLEASE HELP!!! THANKS I GIVE BRAINLIEST !!A student examines the effect of the number of D batteries in a closed circuit on the

brightness of a light bulb. In the experiment, four circuits were built with 1, 2, 3, and 4 batteries respectively. For each trial, the brightness of the light bulb was measured using a light meter. Which variable should the student keep constant
Physics
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

The batteries

Explanation:

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nignag [31]
Understanding with the help of a peer
3 0
4 years ago
Water pressurized to 3 ´ 105 Pa is flowing at 5.0 m/s in a pipe which contracts to 1/3 of its former area. What are the pressure
Vladimir [108]

Answer:

=P' = 2 * 10 ^ 5 Pa

Explanation:

given data:

Pressure P = 3 * 10^ 5 Pa

speed v = 5 m / s

Area A = A

from the information given in equation final Area is 1/3 of initial area i.e.

A ' = A / 3

we know that density of water = 1000 kg / m^ 3

from continuity equation

Av = A ' v'

so we have

speed v ' = 3*A*v / A

v ' = 3*A*5/ A

v = 15 m / s

from bernoulli's equation we can calculate final pressure

Required pressure P ' = P + ( 1/ 2) \rho [ v^ {2} v'^{ 2}]

= P ' = P + ( 1/ 2) \rho_{water} [ v^ {2} - v'^{ 2}]

=P -  10 ^ {5}

= 3*10^{5} - 10 ^ {5}

=P' = 2 * 10 ^ 5 Pa

8 0
4 years ago
Read 2 more answers
A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n
Sholpan [36]

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

5 0
3 years ago
Why is the reflection of a wave at a free boundary different from reflection at a fixed boundary??
Gnoma [55]

Here is the main thing is medium. In the free boundary wave face the air medium, but in a fixed boundary wave face different medium. The change of medium effect on the change of the reflection of wave.

6 0
3 years ago
A circuit has a current of 2.4 A. The voltage is increased to 4 times its original value, while the resistance stays the same.
Ronch [10]

Answer:

Explanation:

d

7 0
3 years ago
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