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kykrilka [37]
2 years ago
5

If a jet is travelling horizontally at 100m/s at a height of 500m above the ground and a jet drops a bomb to the ground. Where d

oes the bomb strike the ground relative to the point atwhich it is released ?A.100m B.1km C.500m D.5km
Physics
1 answer:
Westkost [7]2 years ago
8 0

The bomb strike the ground relative to the point at 1km . B

<h3>How to determine the distance</h3>

Using the equation

h = 1/2 gt^2

500 = 1/2 * 10* t^2

500 = 5t^2

t = √500/5

t = √100

t = 10seconds

To find the distance,

Distance = velocity * time

Distance = 100 ÷ 10

Distance = 1000m = 1km

Therefore, the bomb strike the ground relative to the point at 1km . B

Learn more about projectile distance here:

brainly.com/question/15502195

#SPJ1

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7) If the mass of an object is 694 g, find the mass of rider 1 if rider 2 = 600g rider 3 = 90 (Subtract the smaller numbers from
icang [17]

The mass of the rider 1 is 4 g.

<h3>The use of a rider in mass measurement</h3>

Rider is a metallic wire piece which is of certain mass and can be bent . It can move the beam of the Paul Bunge Balance.

The riders are the sliding pointers positioned on top of the beams to show the pan and beam weight in grams.

<h3>Mass of the rider 1</h3>

The mass of the rider 1 is obtained by subtracting mass of riders as show below.

mass of rider 1 = mass of object - (mass of rider 2 + mass of rider 3)

mass of rider 1 = 694 g  - (600 g + 90 g)

mass of rider 1 = 694 g - 690 g

mass of rider 1 = 4 g

Thus, the mass of the rider 1 is 4 g.

Learn more about use of riders in mass measurement here: brainly.com/question/1747339

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8 0
2 years ago
A ray is incident on a film of thickness t and the index of refraction n=1.6 at an angle θ = 35 degrees. Find the angle of refra
lidiya [134]

Answer

Given,

refractive index of film, n = 1.6

refractive index of air, n' = 1

angle of incidence, i = 35°

angle of refraction, r = ?

Using Snell's law

n' sin i = n sin r

1 x sin 35° = 1.6 x sin  r

 r = 21°

Angle of refraction is equal to 21°.

Now,

distance at which refractive angle comes out

d = 2.5 mm

α be the angle with horizontal surface and incident ray.

α = 90°-21° = 69°

t be the thickness of the film.

So,

tan \alpha = \dfrac{t}{d/2}

tan 61^0 = \dfrac{t}{2.5/2}

t = 2.26 mm

Hence, the thickness of the film is equal to 2.26 mm.

4 0
3 years ago
A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw
galben [10]

Answer:

Part a)

\tau_{net} = 1397.1 Nm

Part b)

I = 702.06 kg m^2

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

\tau_{net} = FL - mg\frac{L}{2}

\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})

\tau_{net} = 1397.1 Nm

Part b)

As per Newton's law we know that

\tau = I\alpha

now we have

1397.1 Nm = I(1.99 rad/s^2)

I = 702.06 kg m^2

6 0
3 years ago
Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the
shutvik [7]

Period = 6 seconds and frequency = 0.167Hz .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of  \frac{1}{t} . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency =   \frac{1}{t}

⇒ frequency = \frac{1}{time}

⇒ frequency = \frac{1}{6}

⇒ frequency = 0.167Hz

Therefore , Period = 6 seconds and frequency = 0.167Hz .

7 0
3 years ago
A physical proprety of gold is its ?
nydimaria [60]
Density because it can measured and felt.
4 0
3 years ago
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