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olganol [36]
2 years ago
13

Kate runs 2/3 of a mile on Mondays, Wednesday's and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. How many miles doe

s Kate run during the week
Mathematics
1 answer:
padilas [110]2 years ago
8 0

Answer:

Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.

Step-by-step explanation:

We know that Kate runs 2/3 of a mile on Mondays, Wednesdays and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. We calculate how many miles does Kate run during the week.  

Therefore, we get

\frac{2}{3}+\frac{4}{5}=\frac{10+12}{15}=\frac{22}{15}=1+\frac{7}{15}

Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.

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Find the area. Round to the nearest tenth.
motikmotik

Answer:

40m^2

Step-by-step explanation:

Hope it helps!!:)

6 0
3 years ago
) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick
Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= \pi (r+\triangle r)^2- \pi r^2

=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]

=\pi [2r\triangle r+(\triangle r)^2]

Since (Δr)² is very small, So it is ignorable.

∴A=2\pi r\triangle r

The density \delta (r)= \frac{40}{1+r^2}

We know,

Mass= Area× density

        =(2r \pi \triangle r)(\frac{40}{1+r^2}})

Total mass M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i

Therefore

\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr

                      =40\pi[ln(1+r^2)]_0^5

                      =40\pi [ln(1+5^2)-ln(1+0^2)]

                     =40\pi ln(26)

                     = 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0
2 years ago
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
2 years ago
NEED HELP ASAP<br> WILL GIVE BRAINLY<br> PLEASE I NEED THIS
Eddi Din [679]
Bmrruray is the answer
4 0
2 years ago
What value of x makes this equation true , use numerals instead of words.<br> -2x+3=-15
uysha [10]

Answer:

x = 9

Step-by-step explanation:

-2x + 3 = -15

-2x = -18

x = 9

7 0
1 year ago
Read 2 more answers
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