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Olenka [21]
3 years ago
5

In triangle ABC shown below, side AB is 8 and side AC is 6:

Mathematics
2 answers:
ira [324]3 years ago
3 0

The answer is C because AD is half of AB and AE is half of AC.

Burka [1]3 years ago
3 0

Answer:  The correct option is

(D) Segment AD is 4, and segment AE is 3.

Step-by-step explanation:  In the given figure, we are shown a triangle ABC with side AB measures 8 units and AC measures 6 units.

We are to select the statement that is needed to prove that segment DE is half the length of segment BC.

<u><em>Midpoint Theorem :</em></u>

The line joining the mid points of any two sides of a triangle is parallel to the third side and is half of the third side.

In triangle ABC, applying the midpoint theorem,

for DE to be half of BC, D must be the midpoint of AB and E must be the midpoint of AC.

If so, then

AD=\dfrac{1}{2}\times AB=\dfrac{1}{2}\times8=4,\\\\\\AE=\dfrac{1}{2}\times AC=\dfrac{1}{2}\times 6=3.

Thus, for DE to be half of BC, segment AD is 4 and segment AE is 3.

Option (D) is CORRECT.

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The solution is x \geq 13.

Solution:

Given inequality:

7 x \geq 91

Divide by 7 on both sides.

$\frac{7 x}{7} \geq \frac{91}{7}

x \geq 13

The solution is x \geq 13.

The image of the graph is attached below.

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2 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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2 years ago
WILL GIVE BRAINLIEST, 5 STARS, AND THANKS
Gelneren [198K]
(5)(6)(8) = 240
240 blocks in one box.
(240)(3) = 720
720 blocks in three boxes
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2 years ago
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Answer:

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2 years ago
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The product of two facters is 7,000. If one of the factors is 90, what is the other factor?
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Let's solve this by creating an equation.


Let X = the second factor

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