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Sloan [31]
3 years ago
5

Need help , on how to do this exactly

Mathematics
1 answer:
Natalka [10]3 years ago
5 0
Only a possible rational root formed as follows:

a factor of the constant term (-3) in the numerator, and
a factor of the leading term (2) in the denominator.

According to these criteria, only 3/2 qualifies.


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The area of a rectangle is 180 cm2. The width of the rectangle is 30 cm. What is the measure of the length of the rectangle
creativ13 [48]
Correct Answer:

C. 6 cm

Work:

Divide 180 by 30
3 0
3 years ago
If x=-3 is the only x intercept of the graph of a quadrant equation which statement best describes the discriminant of the equat
Gala2k [10]

Complete question:

If x = –3 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the equation?

a) The discriminant is negative.

b) The discriminant is –3.

c) The discriminant is 0.

d) The discriminant is positive.

Answer:

c) The discriminant is 0.

Step-by-step explanation:

Here, x = -3 is the only x intercept of graph of a quadrant equation.

In this case the determinant of the quadrant equation will be 0.

i.e, x = 0

The determinant of the quadrant equation will be zero because, since x = -3 is the only x intercept of the graph, the quadrant equation will have equal roots. Also, when there are equal roots in a quadrant equation, the discriminant tends to zero.

Therefore the correct answer is (c) The discriminant is 0.

D = 0

8 0
3 years ago
Read 2 more answers
If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec theta?
faust18 [17]

Answer:

\sec \theta=\dfrac{5}{4}.

Step-by-step explanation:

Use the definition of secans:

\sec \theta=\dfrac{1}{\cos \theta}.

Now you have to find the cosine of angle \theta.

Point (12,-9) lies in fourth quadrant, then \cos \theta>0.

Consider right triangle with legs 9 and 12, by the Pythagorean theorem,

\text{hypotenuse}^2=9^2+12^2=81+144=225,\\ \\\text{hypotenuse}=15.

Thus,

\cos \theta=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{12}{15}=\dfrac{4}{5}

and

\sec \theta=\dfrac{1}{\dfrac{4}{5}}=\dfrac{5}{4}.

4 0
3 years ago
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kobusy [5.1K]

Answer:

perimeter = ( {2x}^{2}  + 3x + 7) + ( {x}^{2}  + 5) \\  = (3 {x}^{2}  + 3x + 12) \: units

6 0
3 years ago
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I<br> b)<br> 3x +<br> 2y = 12<br> x - y = -1
prohojiy [21]

Answer:

x intercept: let y = 0 to get x = 4

y intercept: let x = 0 to get y = -6

Step-by-step explanation:

Hope thois helped you!

5 0
3 years ago
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