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ser-zykov [4K]
2 years ago
6

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Complete this item.

Mathematics
1 answer:
Novay_Z [31]2 years ago
3 0

Answer:  3+\sqrt{2}

Step-by-step explanation:

Given the following expression shown in the picture:

\frac{7}{3-\sqrt{2} }

You need to use a process called "Ratinalization".

By definition, using Rationalization you can rewrite the expression in its simplest form so there is not Radicals in its denominator.

Then, in order to simplify the expression, you can follow the following steps:

<em>Step 1</em>. You need to multiply the numerator and the denominator of the fraction by  3+\sqrt{2}, which is the conjugate of the denominator  3-\sqrt{2}.

<em>Step 2</em>. Then you must apply the Distributive property in the numerator.

<em>Step 3</em>. You must apply the following property in the denominator:  (a+b)(a-b) = a^2 - b^2

Therefore, applying the procedure shown above, you get:

=\frac{(7)(3+\sqrt{2})}{(3-\sqrt{2})(3+\sqrt{2})}=\frac{21+7\sqrt{2}}{3^2-(\sqrt{2})^2}=\frac{21+7\sqrt{2}}{9-2}=\frac{21+7\sqrt{2}}{7}

<em>Step 4</em>.  You can observe that the expression can be simplified even more. Since:

 \frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

You get:

\frac{21+7\sqrt{2}}{7}=\frac{21}{7}+\frac{7\sqrt{2}}{7}=3+\sqrt{2}

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