The answer is b! that is how you measure volume. have a good day and stay safe! :)
Answer:
10mL
Explanation:
Using the formula as follows:
CaVa = CbVb
Where;
Ca = concentration of acid, HBr (M)
Cb = concentration of base, Sr(OH)2 (M)
Va = volume of acid, HBr (Litres)
Vb = volume of base, Sr(OH)2 (Litres)
According to the information given in this question;
Ca = 0.24M
Cb = 0.24M
Va = ?
Vb = 10.0ml
Using CaVa = CbVb
0.24 × Va = 0.24 × 10
0.24Va = 2.4
Va = 2.4 ÷ 0.24
Va = 10mL
10mL of HBr is needed.
Answer:
Alloys and Composites
Explanation:
<u>Drill bits are made of alloys</u> because alloys are very much resistant to corrosion and are created when one or multiple metals are mixed with other elements that are non-metallic in nature. Due to their greater strength, they are used in the power drills in order to create borehole drills at the mining site. Borehole drilling is commonly done in order to understand the sub-surface strata before mining.
<u>The bodies along with the handles of power drills are constructed of composite insulators</u> because within the composites there is the absence of free electrons that has the ability to flow and produce electricity. So they are considered to be used as a good insulator.
Answer:
713.33 g/mol
Explanation:
The<em> freezing-point depression equation</em> is:
Where ΔT is the difference in temperature. The freezing point of pure benzonitrile is -12.75 °C, so ΔT = -12.75 - (-13.8) = 1.05 °C
Kf is the cryopscopic constant, which is 5.35 °C/m (as reported by the CRC Handbook).
m is the molality (moles compound X/kg benzonitrile).
So first we <u>calculate the molality</u>:
Now we <u>calculate the moles of X that were added</u>:
75 g ⇒ 75/1000 = 0.075 kg
- 0.196 m = mol X / 0.075 kg
Finally we <u>calculate the molar mass of X</u>, using the added mass:
- 10.5 g / 0.0147 mol = 713.33 g/mol
Answer:
types of elements nacl MGS
behavior shared between atoms tranferred from one to another
properties high melting poin low melting point
example SI-o metal + non metal
example H-H only non metal elements
Explanation: