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3 years ago

Compare and contrast heat waves and cold waves

1 answer:

7 0

Ok they are both can formed by the same high pressure system . the heat waves are extended periods of above-normal temperatures . but the cold wave is an extended periods of below normal temperatures

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The average rate of disappearance of ozone in the reaction 2o3(g) → 3o2(g) is found to be 7.25×10–3 atm over a certain interval

worty [1.4K]

<h3><u>Answer</u>;</h3>

1.0875 x 10-2 atm

<h3><u>Explanation;</u></h3>

2O3(g) → 3O2(g)

rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t

The average rate of disappearance of ozone ... is found to

be 7.25 × 10–3 atm over a certain interval of time.

This means (ignoring time)

∆[O3]/∆t = -7.25 × 10^–3 atm

(it is disappearing, thus the negative sign)

rate = -(1/2)∆[O3]/∆t

rate = -(1/2)*(-7.25 × 10^–3 atm)

= 3.625 × 10^–3 atm

Now use the other part of the expression:

rate = +(1/3)∆[O2)∆t

3.625 × 10–3 atm = +(1/3)∆[O2)/t

∆[O2)/∆t = (3)*(3.625× 10^–3 atm)

= 1.0875 x 10-2 atm over the same time interval

4 0

3 years ago

A scientist did an investigation on the growth of koi fish. He selected forty newly hatched koi from the same clutch of eggs. He

Luda [366]

D have a good day my dude

8 0

3 years ago

A student observed tiny dots moving about when exploring a drop of pond water. At 400x magnification, the student recognized the

igomit [66]

Paramecia are examples of unicellular organisms. They are protists.

<h3>Protists</h3>

Protists are eukaryotic unicellular (single-celled) organisms that do not fit into any other category.

Paramecia are protists microorganisms generally found in aquatic habitats (e.g., a pond).

Paramecia generally have an oblong shape and they are covered with tiny structures known as cilia (for motion).

Learn more about protists here:

brainly.com/question/12206236

5 0

2 years ago

Calculate each of the following quantities. (a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate WebAssign will check y

ss7ja [257]

Answer:

a) 7.40 grams

b) 0.213 M

c) 102 moles

Explanation:

(a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate

Step 1: Data given

Volume = 175.4 mL = 0.1754 L

Molarity = 0.267 M

Molar mass = 158.17 g/mol

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.267 M * 0.1754 L

Moles = 0.0468 moles

Step 3: Calculate mass

Mass = 0.0468 moles * 158.17 g/mol

<u>Mass = 7.40 grams</u>

b) Molarity of 597 mL solution containing 21.1 g of potassium iodide

Step 1: Data given

Volume = 597 mL = 0.597 L

Mass = 21.1 grams

Molar mass KI = 166.0 g/mol

Step 2: Calculate moles KI

Moles KI = 21.1 grams / 166.0 g/mol

Moles KI = 0.127 moles

Step 3: Calculate molarity

Molarity = moles / volume

Molarity = 0.127 moles / 0.597 L

Molarity = 0.213 M

Step 1: Data given

Volume = 145.6 L

Molarity = 0.703 M

Step 2: Calculate moles

moles = molarity * volume

Moles = 0.703 M * 145.6 L

Moles = 102 moles

8 0

3 years ago

Answer 3 & 4

Anastasy [175]

Answer:

The answer for 2-hexene is that the structure should have 6 carbon with a double bond beginning on the 2nd carbon atom.

The answer for 1-pentyne is that the structure should have 5 carbon with triple bond beginning on the 1st carbon atom.

Explanation:

<u>2-Hexene</u>

The structural formula for 2-hexene will have 6 carbons because the nomenclature has a -hex prefix, which stands for 6 carbons.

The -ene suffix of the nomenclature means that the organic compound is an alkene. Alkenes are hydrocarbons that contain double covalent bond and have the suffix -ene.

The double bond is on the 2 carbon atom because the nomenclature states that the double bond will be on the 2 carbon atom.

<u>1-Pentyne</u>

The structure will have 5 carbons since the -pent prefix means 5 carbons.

The structure has a triple bond because the -yne suffix means that the structure is an alkyne. An alkyne is a hydrocarbon with triple covalent bonds.

Also, the position of the triple bond is known because the nomenclature of the alkyne states that the triple bond is on the 1st carbon.

5 0

3 years ago