We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L
answer:an arrangement of elements in columns, based on a set of properties that repeat from row to row
Explanation:
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A chemical bond is <span> lasting attraction between atoms that enables the formation of </span>chemical <span>compounds. </span>
The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.
The volume of water is
.
Since, 1 gal= 3785.41 mL
Thus, ![2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL](https://tex.z-dn.net/?f=2.29%5Ctimes%2010%5E%7B4%7D%20gal%3D2.29%5Ctimes%2010%5E%7B4%7D%5Ctimes%203785.41%20mL%3D8.66%5Ctimes%2010%5E%7B7%7DmL)
Density of water is 1 g/mL thus, mass of water will be
.
Since, 1 grams of chlorine →
grams of water.
1 g of water →
g of chlorine and,
of water →86.6 g of chlorine
Since, the solution is 9% chlorine by mass, the volume of solution will be:
![V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B100%7D%7B9%7D%5Ctimes%2086.6%20mL%3D9.62%5Ctimes%2010%5E%7B2%7D%20mL)
Thus, volume of chlorine solution is 9.62\times 10^{2} mL.
Answer:
It depends what other values you have. Can you give more info? If they give density then you can solve for m.