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3 years ago

14

How to find formula for ionic compounds.

1 answer:

Umnica [9.8K]3 years ago

5 0

Answer:

I am using an example for this in this table it works for any other compound as well.

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Lakes that have been acidified by acid rain can be neutralized by limiting the addition of limestone how much limestone is requi

svet-max [94.6K]

From the given pH, we calculate the concentration of H+:
[H+] = 10^-pH = 10^-5.5
We then use the volume to solve for the number of moles of H+:
moles H+ = 10^-5.5M * 4.3x10^9 L = 13598 moles
From the balanced equation of the neutralization of hydrogen ion by limestone written as
CaCO3(s) + 2H+(aq) → Ca2+(aq) + H2CO3(aq)
we use the mole ratio of limestone CaCO3 and H+ from their coefficients, which is 1 mole of CaCO3 is to react with 2 moles of H+, to compute for the mass of the limestone:
mass CaCO3 = 13598mol H+(1mol CaCO3/2mol H+)
(100.0869g CaCO3/1mol CaCO3)(1kg/1000g)
= 680 kg

4 0

3 years ago

How much positive charge is in 1.4 kg of oxygen? The atomic weight (15.9994 g) of oxygen contains Avogadro’s number of atoms, wi

Cerrena [4.2K]

Answer:

$6.7511\times 10^7\ C$

Explanation:

The atomic weight of oxygen = 15.9994 g

This mass corresponds to 1 mole of the oxygen atoms.

Thus,

15.9994 g mass of oxygen contains $6.02\times 10^{23}$ atoms of oxygen.

1.4 kg = 1400 g ( 1 kg = 1000 g)

So,

1400 g mass of oxygen contains $\frac {6.02\times 10^{23}}{15.9994}\times 1400$ atoms of oxygen.

Number of atoms in 1400 g of oxygen = $526.769754\times 10^{23}$

Also, 1 atom of oxygen contains 8 protons

Charge of 1 proton = + $1.602\times 10^{-19}\ C$

So, Charge on 1 atom of oxygen = $8\times 1.602\times 10^{-19}\ C$

Thus,

Charge on $526.769754\times 10^{23}$ atoms of oxygen = $526.94476\times 10^{23}\times 8\times 1.602\times 10^{-19}\ C=6.7533\times 10^7\ C$

Thus, positive charge in 1.4 kg of oxygen = $6.7511\times 10^7\ C$

5 0

3 years ago

Acid dissociation reaction for E-amino group (side chain of Lys): (R)E-NH3+ # (R)E-NH2 + A. For a weak acid such as the side cha

Andrew [12]

Answer:

0.1

Explanation:

$According \ to \ Henderson \ Hasselbalch \ equation:$

$pH = pka + log \dfrac{[A^-]}{[HA]}$

From the given question;

$log \dfrac{[\varepsilon- NH_2]}{[\varepsilon - NH_3^+]}=pH - pKa$

$\implies log \dfrac{[\varepsilon- NH_2]}{[\varepsilon - NH_3^+]}=9 -10$

$\implies log \dfrac{[\varepsilon- NH_2]}{[\varepsilon - NH_3^+]}=-1$

$\implies \dfrac{[\varepsilon- NH_2]}{[\varepsilon - NH_3^+]}=10^{-1}$

$\implies \dfrac{[\varepsilon- NH_2]}{[\varepsilon - NH_3^+]}=0.1$

7 0

3 years ago

23. Select the evidence that Thomson used to conclude his findings.

Ilya [14]

Answer:

The answer is C

Explanation:

Thomson conducted many tests with cathode rays. Which led to his discovery of the electron.

8 0

3 years ago

Thisss for you blake :)))

Lady_Fox [76]

I’m not Blake but ok

4 0

3 years ago

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