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Lyrx [107]
2 years ago
15

2x-y=52x-2y=4

3D%204" id="TexFormula1" title="2 \times - y = 5 \\ 2 \times - 2y = 4" alt="2 \times - y = 5 \\ 2 \times - 2y = 4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
7 0
\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right
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A square part of side 20 meters has a footpath along the boundary of width 10 meters . Find the area of path
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Answer:

Answer: 84 meters squared. (i.e. 84m^2).

Step-by-step explanation:

Area of the path = total area of path and plot - plot area only

First, let’s find the area of the plot:

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The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).

The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’

22m x 22m = 484m^2

So:

Area of the path = total area of path and plot - plot area only

= 484 - 400 = 84m^2

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