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Lyrx [107]
3 years ago
15

2x-y=52x-2y=4

3D%204" id="TexFormula1" title="2 \times - y = 5 \\ 2 \times - 2y = 4" alt="2 \times - y = 5 \\ 2 \times - 2y = 4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0
\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right
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Sam correctly answered 80% of the questions on his last math test if he missed 3 problems how many questions were on the test
Dominik [7]
Hello There!

100% - 80% = 20%
20% = 3
Therefore, 10% = 1.5
100% = 10 x 10%
100% = 10 x 1.5
100% = 15.

There were 15 questions.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
6 0
4 years ago
The library is 5 miles from the post office.How many yards is the library from the post office
Naily [24]
1 mile= 1760

5 miles= 8800
6 0
3 years ago
Please answer my questionnn
Kaylis [27]
Hey There,

This is a subtracting fractions problem.

Solutions-

1. <span>Convert 5 \frac{7}{10} to an improper question. You do this by multiplying       the denominator and the whole number and adding that number to the numerator.    The improper fraction would be \frac{50}{7}</span>

2. Now, subtract \frac{140}{0}- \frac{15}{10} 

3. The answer to step two should be \frac{125}{10}

Thus, the answer should be \frac{125}{10}=12 \frac{1}{2}

In conclusion, Jeff drives 12\frac{1}{2} miles farther then her sister.

Thank You!
5 0
3 years ago
Is this a function?
allsm [11]
A function is where each input (x) has only 1 output (y). Since no x values have more than one y value, this is a function (answer A)
5 0
3 years ago
Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)
vredina [299]

hello ....

the equation of a plane that is ;  ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4  b= -4  c = -1

then: the equation of a plane that is ;  -4x-4y-z +d =0

but the plane  passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

5 0
4 years ago
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