Answer:
The speed and direction of each ball after the collision is 1.27 m/s to East direction and 5.07 m/s to East direction.
Explanation:
given information
m₁ = 0.440 kg
v₁ = 3.80 m/s
m₂ = 0.220 kg
v₂ = 0
collision is perfectly elastic
v₁ - v₂ = - (v₁'- v₂')
v₁ = - (v₁'- v₂')
v₂' = v₁ + v₁'
according to momentum conservation energy
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ = m₁v₁' + m₂(v₁ + v₁')
m₁v₁ = m₁v₁' + m₂v₁ + m₂v₁'
m₁v₁ - m₂v₁ = m₁v₁' + m₂v₁'
v₁ (m₁ - m₂) = (m₁ + m₂) v₁'
v₁' = (m₁ - m₂)v₁ / (m₁ + m₂)
= (0.440 - 0.220) (3.8) / (0.440 + 0.220)
= 1.27 m/s to East direction
v₂' = v₁ + v₁'
= 3.8 + 1.27
= 5.07 m/s to East direction
