Answer:
λ = 548.7 nm
Explanation:
Hi!
First we want to know how much energy we need to remove 1 electron from the surface of the solid:
218.1 kJ/mol => 218 100 J / (6.022 x 10^23) electrons
= 3.621 x 10^-19 J/electron
That is we need 3.621 x 10^-19 J to remove one electron
Now we can calculate the wavelength that a photon must have in order to have this energy:
E = (hc) / λ
λ = (hc) / Ε
where
h = 6,626070150(69) ×10 -34 Js (wikipedia)
c = 3 x10^8 m/s
hc = 1.987 x 10^-25 Jm
Therefore:
λ = ( 1.987 x 10^-25 /3.621 x 10^-19 ) m = 5.487 x 10^-7 m
λ = 548.7 nm
The question is poorly written.
ALL of the choices cause a change in something.
A). Force causes a change in velocity.
B). and C). Power and energy cause changes requiring work.
D). Impulse causes a change in momentum.
Answer: Inertia
Explanation: Objects to stay in motion or at rest unless there is an external unbalanced force aced upon the object.
Explanation:
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 30 m/s
- Mass (m) = 2400 kg
- Force (F) = 12000 N
Let us find the time taken first.
→ F = ma
- Acceleration (a) = (v – u)/t
→ 12000 = 2400 × (30 – 10)/t
→ 12000 ÷ 2400 = (20)/t
→ 5 = 20/t
→ 5t = 20
→ t = 20 ÷ 5
→ <u>t</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>seconds</u>
Now, find the acceleration.
→ a = (v – u)/t
→ a = (30 – 10)/4
→ a = 20/4
→ <u>a</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>m</u><u>/</u><u>s²</u>
Now, by using the third equation of motion,
→ v² – u² = 2as
→ (30)² – (10)² = 2 × 5 × s
→ 900 – 100 = 10s
→ 800 = 10s
→ 800 ÷ 10 = s
→ <u>8</u><u>0</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>s</u>
Therefore, distance travelled is 80 m.
Answer:
K_{f} / K₀ =1.12
Explanation:
This problem must work using the conservation of angular momentum (L), so that the moment is conserved in the system all the forces must be internal and therefore the torque is internal and the moment is conserved.
Initial moment. With arms outstretched
L₀ = I₀ w₀
the wo value is 5.0 rad / s
final moment. After he shrugs his arms
= I_{f} w_{f}
indicate that the moment of inertia decreases by 11%
I_{f} = I₀ - 0.11 I₀ = 0.89 I₀
L_{f} = L₀
I_{f} w_{f} = I₀ w₀
w_{f} = I₀ /I_{f} w₀
let's calculate
w_{f} = I₀ / 0.89 I₀ 5.0
w_{f} = 5.62 rad / s
Having these values we can calculate the change in kinetic energy
/ K₀ = ½ I_{f} w_{f}² (½ I₀ w₀²)
K_{f} / K₀ = 0.89 I₀ / I₀ (5.62 / 5)²
K_{f} / K₀ =1.12