Answer:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Step-by-step explanation:
Let's define the events:
L: The student is proficient in reading
M: The student is proficient in math
The probabilities are given by:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Answer:
Step-by-step explanation:
1000000000000000
---------------------
given:
= cost of Brazilian coffee in mixture
= cost of Venezuelan coffee in mixture
= cost of mixture
---------------------
Now I can rite these equations:
(1)
(2)
Multiply both sides of (2) by and
subtract from (1)
(1)
(2)
and, since
288 kg of Brazilian coffee and 96 kg of Venezuelan coffee are needed
Answer:
We conclude that the numerator of a rational number 8 will be 8.
Step-by-step explanation:
We know that any number which can be written in the form p/q is called a rational number.
i.e. p/q
Where p and q are integers and q≠0.
Here:
Given the number
8
As number '8' can be written in the form p/q, so it is a rational number.
i.e. 8/1
Thus,
Therefore, we conclude that the numerator of a rational number 8 will be 8.
