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yaroslaw [1]
3 years ago
14

The solution to (d+4)^2=9 is D=

Mathematics
2 answers:
Allushta [10]3 years ago
4 0

Answer:

\boxed{\sf d = -1 \ \ \ or \ \ \ d = -7}

Step-by-step explanation:

\sf Solve \:  for  \: d  \: over  \: the  \: real  \: numbers: \\  \sf \implies {(d + 4)}^{2}  = 9 \\  \\  \sf Take  \: the \:  square  \: root \:  of  \: both \:  sides: \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{9}  \\  \\  \sf 9 =  {3}^{2} :   \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{ {(3)}^{2} }  \\  \\  \sf \implies d + 4 =  \pm 3 \\  \\  \sf \implies d + 4 = 3 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + 4 =  - 3 \\  \\  \sf Subtract  \: 4  \: from \:  both \:  sides:   \\ \sf \implies d + (4  - 4)= 3 - 4 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + (4 - 4) =   - 3  - 4  \\  \\ \sf \implies d =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d  =  - 7

bonufazy [111]3 years ago
3 0
Answer
d = -1 or d = -7
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