<span>Orthocenter is at (-3,3)
The orthocenter of a triangle is the intersection of the three heights of the triangle (a line passing through a vertex of the triangle that's perpendicular to the opposite side from the vertex. Those 3 lines should intersect at the same point and that point may be either inside or outside of the triangle. So, let's calculate the 3 lines (we could get by with just 2 of them, but the 3rd line acts as a nice cross check to make certain we didn't do any mistakes.)
Slope XY = (3 - 3)/(-3 - 1) = 0/-4 = 0
Ick. XY is a completely horizontal line and it's perpendicular will be a complete vertical line with a slope of infinity. But that's enough to tell us that the orthocenter will have the same x-coordinate value as vertex Z which is -3.
Slope XZ = (3 - 0)/(-3 - (-3)) = 3/0
Another ick. This slope is completely vertical. So the perpendicular will be complete horizontal with a slope of 0 and will have the same y-coordinate value as vertex Y which is 3.
So the orthocenter is at (-3,3).</span>
That’s easy just look at the point on the graph and see where they are places me
Answer:
<em>5,086.8cm³</em>
Step-by-step explanation:
Given the following
radius of the cylinder r = 9cm
Height of the cylinder h = 20cm
Volume of a cylinder = πr²h
Substitute:
V = π(9)²(20)
V= 3.14 * 81 * 20
<em>V = 5,086.8cm³</em>
<em>Hence the volume of the cylinder is 5,086.8cm³</em>
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When graph crosses y-axis, x=0
<span>-2x+2y=4
</span><span>-2*0+2y=4
2y=4
y=2
x=0, y=2,
so point is (0,2).</span>
The answer is in the photo above
