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3 years ago

Create a scatter plot using the data in the table above.

Mathematics

1 answer:

GalinKa [24]3 years ago

7 0

Answer:

Step-by-step explanation:

A scatter plot is a chart type that is normally used to observe and visually display the relationship between variables. It is also known as a scattergram, scatter graph, or scatter chart

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I need this fast!........................

Schach [20]

Answer: $(2,2)$

Step-by-step explanation:

1. Substitute $y=0$ into first equation and solve for "x" in order to find the x-intercept of the first line:

$0=-\frac{1}{2}x+3\\\\-3=-\frac{1}{2}x\\\\(-3)(-2)=x\\\\x=6$

2. Substitute $x=0$ into the first equation and solve for "y" in order to find the y-intercept of the first line:

$y=-\frac{1}{2}(0)+3\\\\y=3$

Knowing that first line passes through the points $(6,0)$ and $(0,3)$ , you can graph it.

3. Substitute $y=0$ into second equation and solve for "x" in order to find the x-intercept:

$0=2x-2\\\\2=2x\\\\x=1$

4. Substitute $x=0$ into the second equation and solve for "y" in order to find the y-intercept of the second line:

$y=2(0)-2\\\\y=-2$

Knowing that second line passes through the points $(1,0)$ and $(0,-2)$ , you can graph it.

The solution of the system of equations is the point of intersection between the lines. Therefore, the solution of this system is:

$(2,2)$

7 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

Write an equation of a line that passes through (-3,1), perpendicular to Y=-3x-3

Sever21 [200]

Answer:

Step-by-step explanation:

To be perpendicular, the product of the slope is -1.
(x,y) Substituting the coordinates.
y= 1/3(x+3) + 1
y= 1/3x +2

5 0

2 years ago

Read 2 more answers

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

3 years ago

The regular price of a pair of glasses is $90. The glasses are on sale for a discount price of $76.50 What is the percent of the

natima [27]

Answer:

15%

Step-by-step explanation:

$\frac{76.50}{90}=\frac{x}{100}$ Set up a proportion.