<span>An experiment designed so that you can observe the differences between the experimental group and the control group.
In each experiment there have to be two groups - an experimental one (which has a different variable), and a control group. Both of these groups are subjected to the same thing except for that variable you are trying to test via an experiment.
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So let's make p = dominant allele and q = recessive allele
p+q = 1, and (p+q)^2 = 1^2 thus
p^2 + 2pq + q^2 = 1, where p^2 = homozygous dominant, 2pq = heterozygous, and q^2 = homozygous recessive
So if p = .84, then q = 1-.84 = .16
a) recessive phenotype = q^2 = (.16)^2 = .0256
= 2.6%
b) dominant allele = p = .84 = 84%
c) heterozygous genotype = 2pq = 2(.84)(.16)
= .269 = 26.9%
Organizing is the second part of the perception process, in which we sort and categorize information that we perceive based on innate and learned cognitive patterns. Three ways we sort things into patterns are by using proximity, similarity, and difference (Coren, 1980
Answer:
Part A;
k = -1
Part B
k = -4
Part C
g(x) = 3ˣ - 1
h(x) = 
Explanation:
The parent function of the graph, is f(x) = 3ˣ
Part A;
g(x) = f(x) + k
When x = 0, f(x) = 3⁰ = 1
g(x) = f(x) + k = 
+ k
Therefore;
When x = 0, g(0) = f(0) + k = 
+ k = k
From the graph, g(0) = -1, therefore;
g(0) = -1 = k
k = -1
Part B
h(x) = f(x + k)
When x = 4, h(4) = f(4 + k) = 
From the graph, h(4) = 1, therefore;
h(4) = 1 =
Therefore, we get;
ln(1) = (4 + k)·ln(3)
4 + k = ln(1)/ln(3) = 0
k = 0 - 4 = -4
k = -4
Part C
g(x) = f(x) + k
f(x) = 3ˣ, and k = -1
Therefore;
g(x) = 3ˣ - 1
h(x) = f(x + k)
f(x) = 3ˣ, and k = -4
Therefore;
h(x) =
