Answer:
x = -3
, y = 0
Step-by-step explanation:
Solve the following system:
{4 x - y = -12 | (equation 1)
-x - y = 3 | (equation 2)
Add 1/4 × (equation 1) to equation 2:
{4 x - y = -12 | (equation 1)
0 x - (5 y)/4 = 0 | (equation 2)
Multiply equation 2 by 4/5:
{4 x - y = -12 | (equation 1)
0 x - y = 0 | (equation 2)
Multiply equation 2 by -1:
{4 x - y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -3 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = -3
, y = 0
Answer:
Step-by-step explanation:
Given the following simplified expressions:
4√3, 3 3√2, 2 3√3, 3√5
It's radical equivalent is :
4√3 = √4² * √3 = √16 * √3 = √16*3 = √48
3 3√2 = 3 * √3² * √2 = √9 * √2 = √9*2 = 3√18
2 3√3 = 2 * √3² * √3 = √9 * √3 = √9*3 = 2√27
3√5 = √3² * √5 = √9 * √5 = √9*5 = √45
For it to be non-linear, the rate of change cannot be constant. For the first table the rate is a constant 1 and the second table has a constant rate of -1. The 3rd and 4th tables have no constant rate and thus are non-linear.
The 4th table is increasing while the 3rd table is decreasing.
So the 3rd table, Set C, is the only non-linear negative association between x and y.
C were Muslims pray hope this helps