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3 years ago

14

PLEASE HELP!! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the trigonometric rat

ios with their values based on the triangle shown in the diagram

1 answer:

Monica [59]3 years ago

6 0

this is the answer on edmentum

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5t-14=-14<br> solve the equation for t

ikadub [295]

Hi there!

Before we begin, let's rewrite your equation. :)

$5t - 14 = -14$

Step 1) Add 14 to both sides.

$5t - 14 + 14 = -14 + 14 5t = 0$

Step 2) Divide both sides by 5.

$\frac{5t}{5} = \frac{0}{5}$

$t = 0$

Final Answer -

$t = 0$

Hope this helps!

Message me if you need anymore help! :D

3 0

4 years ago

Which table represents a nonlinear function?

Setler [38]

Answer:

A

Step-by-step explanation:

Nonlinear would be any function where both values are not changing by some fixed amount. In B, f(x) increases by 1 for every time x increases by 1 so that's linear. For C, f(x) increases by 2 for every time x increases by 1, so that's linear. For D, f(x) increases by 3 for every time x increases by 1 so that's also linear. For A, f(x) does not always change by the same amount, so it's nonlinear.

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3 years ago

How can using reciprocals help you divide fractions

tresset_1 [31]

When you divide fractions, you change each to its reciprocal, then you look multiply them. Using reciprocals helps you easily solve the problem.

7 0

3 years ago

Which equation is an identity?

spayn [35]

7z + 10 - z = 8z - 2(z - 5)
7z + 10 - z = 8z - 2z + 10
6z + 10 = 6z + 10
6z - 6z = 10 - 10
0 = 0

Therefore, 7z + 10 - z = 8z - 2(z - 5)

3 0

3 years ago

Math help please TY :3<br><br> HWAJDSK 10 POINTS REWARDING !!

valkas [14]

I will do Point A carefully, The others I will indicate. Start with the Given Point A. Then do the translations

A(-1,2) Original Point

Reflection: about x axis:x stays the same; y becomes -y:Result(-1,-2)

T<-3,4>: x goes three left, y goes 4 up (-1 - 3, -2 + 4): Result(-4,2)

R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)

B(4,2) Original Point

Reflection: (4, - 2)
T< (-3,4): (4-3,-2 + 4): (1 , 2)
R90 CCW: (-y,x) = (-2 , 1)

C(4, -5) Original Point

Reflection (4,5)
T<-3,4): (4 - 3, 5 + 4): (1,9)
R90, CCW (-9 , 1)

D(-1 , -5) Original Point

Reflection (-1,5)
T(<-3,4): (-1 - 3, 5 + 4): (-4,9)
R90, CCW ( - 9, - 4)

Note: CCW means Counter Clockwise

The graph on the left is the same one you have been given.

The graph on the right is the same figure after all the transformations

7 0

3 years ago