Let t be time in hours.
Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.
Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.
Train B will overtake train A when their distances from the station are equal.

Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at
12:00.
Uhhh, if you guys are doing means(or averages) in class, then add .39+.72 to get 1.11. Then divide by two.
The answer is 25%
you take (425/1700)*100
0.25 * 100% = 25%
Some schools do this differently, but since I don’t have any of the answer choices I’ll show you how to
Factor: -6|x+5|-2
Factor out the two
2(-3|x+5|-1)
And if you are looking for a graph here: