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gogolik [260]
3 years ago
10

The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $5.50 and

each adult ticket sells for $10. The auditorium can hold at most 140 people. The drama club must make no less than $1100 from ticket sales to cover the show's costs. If
xrepresents the number of student tickets sold and
y represents the number of adult tickets sold, write and solve a system of inequalities graphically and determine one possible solution.
Mathematics
2 answers:
Pani-rosa [81]3 years ago
4 0

Answer:

i dont know

Step-by-step explanation:

:0

artcher [175]3 years ago
3 0

Answer:

x=66 y=74

Step-by-step explanation:

5.5x + 10y = 1100

x + y = 140

---

y = 140 - x

---

5.5x + 10(140-x) = 1100

5.5x + 1400 - 10x = 1100

-4.5x = -300

x = 66.67

---

x = 66

y = 74

= $1103

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1/4 + 1/6= ?<br><br> Help and im to lazy :p
Vera_Pavlovna [14]
Make bottom number de same

1/4 times 6/6=6/24
1/6 times 4/4=4/24



now we gots
1/4+1/6=
6/24+4/24=
(6+4)/24=
10/24=
5/12
8 0
3 years ago
A plane flew 145km/h faster when it was flying with the wind than it would have flown with still air, if it’s speed with the win
pshichka [43]

Answer:

Speed of plane in still air = 825 km/h

Step-by-step explanation:

Given:

Speed of plane with the wind is 145 km/h faster than what it would have with still air.

Speed of plane with wind = 970 km/h

To find speed of plane in still air.

Solution:

Let speed of plane in still air be = x km/h

Thus speed of plane with wind would be given as = (x+145) km/h

Speed of plane with wind is given =970 km/h

So, we have:

x+145=970

Solving for x.

Subtracting both sides by 145.

x+145-145=970-145

∴ x=825 km/h (Answer)

Thus, speed of plane in still air = 825 km/h

8 0
3 years ago
8k - 3 - 10 ( I have to simplify it)
Serga [27]

8k - 3 - 10

Solution,

= 8k - 3 - 10

= 8k - 13.

7 0
3 years ago
-6+ (-20) + (-40) + 3d
cupoosta [38]

Answer:

-3(22-d) ?

Step-by-step explanation:

I hope this is right please let me know

8 0
3 years ago
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year f
MA_775_DIABLO [31]

Answer:

Option D is the correct answer.

Step-by-step explanation:

Initial height = 4 feet

Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

Let the rate of growing each year be g.

After 6 years height of tree = 4 + 6g

After 4 years height of tree = 4 + 4g

At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

That is

                4+6g=4+4g+\frac{4+4g}{5}\\\\4+6g=\frac{20+20g+4+4g}{5}\\\\20+30g=24+24g\\\\6g=4\\\\g=\frac{2}{3}ft/year

Option D is the correct answer.    

8 0
3 years ago
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