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Marina CMI [18]
3 years ago
5

Need help with math problem please

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
P= -8, 3
q= -3, 3
r= 1, 6
s= -4, 6
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Explain how the ratios 5 tacos for every 2 guest and 2 tacos for every 5 guests are different. Include a model in your explanati
maria [59]

Answer:

5 tacos for 2 guests would mean more for each person, while 2 tacos for 5 guests would mean less for each person

6 0
3 years ago
Factor of 169 and 9 squared
emmasim [6.3K]

Answer:

The greatest common factor of 169 and 81 is 1.

Step-by-step explanation:

9 squared is 81 and the greatest common factor of 169 and 81 is one. They have no other common factors. Please mark me brainliest and I hope this helps!

3 0
3 years ago
ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
3 years ago
Help please for homework
krek1111 [17]
4 + 3m and 2x + 3y. Sum means addition
5 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Maslowich

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

3 0
3 years ago
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