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Marina CMI [18]
3 years ago
5

Need help with math problem please

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
P= -8, 3
q= -3, 3
r= 1, 6
s= -4, 6
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A swimming pool is being drained so it can be cleaned. The amount of water in the pool is changing according to the función f(t)
TiliK225 [7]

Answer:

0 ≤ t ≤ 5.

Step-by-step explanation:

In the function f(t), t is the independent variable. The domain of f is the set of all values of t that this function can accept.

In this case, f(t) is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,

  • t \ge 0.
  • f(t) \ge 0.

The first condition is an inequality about t, which is indeed the independent variable.

However, the second condition is about f, the dependent variable of this function. It has to be rewritten as a condition about t.

\begin{aligned} f(t) &\ge 0 &&\text{Assumption} \cr 80000 - 16000\, t& \ge 0 && \text{Definition of} ~ f \cr 80000 & \ge 16000\, t && \begin{aligned}&\text{Add $16000\, t$} \\[-0.5em] & \text{to both sides of the inequality}\end{aligned} \cr 5 &\ge t &&\begin{aligned}&\text{Divide both sides of} \\[-0.5em] & \text{the inequality by $16000$}\end{aligned} \cr t &\le 5 && \text{Flip the inequality}\end{aligned}.

Hence, t ≤ 5.

Combine the two inequalities to obtain the domain:

0 ≤ t ≤ 5.

6 0
3 years ago
Jermaine has just painted a large mural. It's 8 1/2 feet wide the wall he wants to place it on is 11 3/4 feet wide.Ahout how far
Fittoniya [83]
About 1.63 ft.
First subtract 8.5 from 11.75 which is 3.25
then divide 3.25 by 2 which is 1.625
Therefore about 1.63 ft. away from each side.
3 0
3 years ago
Question 1<br> (n - 3)(2n + 6)<br> 18n2 - 45n + 25
DENIUS [597]
(n-3) 2n+6)
18n2-45n+25

8n-18n2-45n+25
8n-18n2
8-45n=37
37+25=62
7 0
2 years ago
Read 2 more answers
PLEASE LOOK AT PICURE!!! I WILL MARM BRAINIEST TO WHOEVER IS CORRECT!!!
dexar [7]

Answer:

Angle 2 is 36 degrees

Step-by-step explanation:

73 - 37 = 36

3 0
2 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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