Answer:
believe it's G, I hope that's correct for you
Answer:
Side a = 35ft
Side b = 35ft
Side c = 20ft
Step-by-step explanation:
The formula for the perimeter of a triangle = Side a + Side b + Side c
In an isosceles triangle, 2 sides are equal to each other.
So, Side a = Side b
In the question, we are told that:
The two equal sides are each 5 ft less than twice the length of the third side.
Hence,
a = 2c - 5
b = 2c - 5
P = 90ft
P = a + b + c
90 = 2c - 5 + 2c - 5 + c
Collect like terms
90 = 5c - 10
90 + 10 = 5c
100 = 5c
c = 100/5
c = 20
The length of the third side = 20ft
a = 2c - 5
= 2 × 20 - 5
= 40 - 5
= 35 ft
b =2c - 5
= 2 × 20 - 5
= 40 - 5
= 35 ft
Therefore,
Side a = 35ft
Side b = 35ft
Side c = 20ft
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:
y= (3/2)x-3
Step-by-step explanation:
We need two points to find the equation of a line. Let's take (2,0) and (4, 3).
In the equation y=mx+b, m represents the slope. To find the slope, we can calculate the change in y/change in x. For (2,0) and (4,3), the change in y is 3-0=3 and the change in x is 4-2=2. Therefore, our slope is 3/2.
Then, in the equation y=mx+b, we can plug 3/2 in for m to get y = (3/2)x+b. To find b, we can plug one point in, such as (2.0), to get 0=(3/2)(2) + b, 0=3+b, and b=-3, making our equation
y= (3/2)x-3
Answer:
Draw a right triangle such that the distance between the two points is the hypotenuse. Hence, When you use the distance formula, you are calculating the length of the Hypotenuse of a right triangle.